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MatroZZZ [7]
3 years ago
10

Does anyone else like online.... oooor is just me

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
4 0
Online what? if you mean online school yeah i kinda like it better
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In the expansion of
Mumz [18]

By the binomial theorem, the x^2 term in the expansion of \left(1-\frac x4\right)^n is

\dbinom n21^{n-2}\left(-\dfracx4\right)^2=\dfrac{n!}{2!(n-2)!}\dfrac{x^2}{16}

which suggests that the contribution of the binomial coefficient should make up the remaining factor of 21. That is,

\dfrac{n!}{2!(n-2)!}=\dfrac{n(n-1)}2=21\implies n=7

5 0
3 years ago
Find the value of y when x equals 17 -x+y=-27
notka56 [123]
Find the value of y when x equals 17 -x+y=-27
since x is equal to 17 you plug it in the equation as follows...
-17+y=-27
then you add 17 on both sides...
y=-27+17
Answer:
y=-10
6 0
3 years ago
If I place $2,000 in my retirement account at the beginning of each year for 10 years. The account will earn 5 percent interest
Norma-Jean [14]

Answer:

poooooooooooop

Step-by-step explanation:

6 0
3 years ago
Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6
Anettt [7]
Splitting up the interval [0, 6] into 6 subintervals means we have

[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]

and the respective midpoints are \dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2. We can write these sequentially as {x_i}^*=\dfrac{2i+1}2 where 0\le i\le5.

So the integral is approximately

\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2

Recall that

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6
\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2
\displaystyle\sum_{i=1}^n1=n

so our sum becomes

\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)
=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2

8 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B14-7x%7D%7B7%7D" id="TexFormula1" title="\frac{14-7x}{7}" alt="\frac{14-7x}{
BartSMP [9]

Answer:

<h2><u><em>2-x</em></u></h2>

Step-by-step explanation:

(14 - 7x)/7 =

[7(2-x)]/7 =

2-x

4 0
2 years ago
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