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ss7ja [257]
3 years ago
8

Difference between load and effort​

Physics
1 answer:
Mashutka [201]3 years ago
3 0
Answer. Is that load is a burden; a weight to be carried while effort is the work involved in performing an activity; exertion.
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I have a massive rock weighing 3,000 Newtons but I can only accelerate it to 500 m/s2 what is its mass?
jeka57 [31]

Answer:

6 kg

Explanation:

F=ma

F is Force(newtons)

m is mass(kg)

a is acceleration(m/s^2)

Plug in the numbers

3000 = m(500)

divide both sides by 500 to cancel out the 500.

3000/500=6

6 = m

6kg is the mass

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Why is blood important
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5 0
3 years ago
Can you please help me ASAPPP !!
Natali5045456 [20]

Answer:

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5 0
3 years ago
William finds a piece of pure iron in his garden. After a few days, the iron begins to rust. What are the two types of substance
nordsb [41]
Answer: an element; a compound
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8 0
3 years ago
*Look at attachment for photo of object**
prohojiy [21]

A. The magnitude of the spring force (in N) acting upon the object is 15.9 N

B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²

C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).

<h3>A. How to determine the force </h3>
  • Extension (e) = 0.150 m
  • Spring constant (K) = 106 N/m
  • Force (F) = ?

F = Ke

F = 106 × 0.15

F = 15.9 N

<h3>B. How to determine the acceleration</h3>
  • Mass (m) = 0.52 Kg
  • Force (F) = 15. 9 N
  • Acceleration (a) =?

F = ma

Divide both sides by m

a = F / m

a = 15.9 / 0.52

a = 30.58 m/s²

<h3>C. How to determine the direction of the acceleration vector</h3>

Considering the diagram, we can see that the spring was pulled away from the equilibrium point.

Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.

Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

3 0
2 years ago
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