Answer:
200 m/min.
Explanation:
From the question given, we obtained the following data:
Total distance = 2 km
Total time = 2 + 4 + 1 + 3
Total time = 10 mins
Average speed =.?
Next, we shall convert 2 km to metre (m). This can be obtained as follow:
1 km = 1000 m
Therefore,
2 km = 2 km × 1000 m / 1 km
2 km = 2000 m
Therefore, 2 km is equivalent to 2000 m.
Finally, we shall determine the average speed of Cindy as follow:
Total distance = 2000 m
Total time = 10 mins
Average speed =.?
Average speed = Total distance /total time
Average speed = 2000 /10
Average speed = 200 m/min.
Therefore, the average speed of Cindy is 200 m/min.
Answer:
volume : {l}^3
speed: (l)^1*(t)^-1
Explanation:
Volume is a measure of 3 dimensional space. It is expressed with 3 orthogonal lengths. The volume of a box would be the product of it's height, width and length. These 3 are longitudes that can be expressed in meters, feet, inches, etc. Because these are 3 longitudes multiplied the result will be a cubic longitude (l)^3.
A more general method for finding a volume is to use integral calculus:
This is for Cartesian coordinates. Cylindrical and spherical coordinates can also be used.
Speed is defined as the rate of change in position respect of time:
For movement in one dimension.
For movement in 3 dimensions you calculate the speed component of each space direction and express them as components of a speed vector:
This is a vector of velocity components, each one is expressed as a division of a longitude over a time, so speed components have dimensions of (l)^1*(t)^-1
The speed vector has a magnitude that is obtained with the Pitagoras theorem:
Since each component is squared, added together and then the square root is taken this magnitude is also in (l)^1*(t)^-1
Answer:
is called <em>matter</em> :)
Explanation:
Answer:
the magnitude of the angular magnification of the telescope. is 4
Explanation:
Calculate the magnitude of the angular magnification of the telescope.
Given that,
distance = 25cm
focal length from the objective f₀ = 20cm
focal length from eye piece f₁ = 5cm
The angular magnification of the telescope is
Magnification = 20 / 5
magnification = 4
Hence, the magnitude of the angular magnification of the telescope. is 4