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3 years ago

WHICH ROLLER COASTER CART HAS THE LEAST POTENTIAL ENERGY DUE TO GRAVITY?

Physics

1 answer:

DIA [1.3K]3 years ago

6 0

Answer:

C. Car A

Explanation:

if the answer is: which roller coaster car has the greatest potential energy due to gravity brainly

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Write one to two sentences explaining whether this passage from the story is exposition, rising action, climax, or resolution: “

fiasKO [112]

Answer:

This passage is part of the resolution because it shows what happens after the climax. It wraps up the conflict, and then the story is over.

Explanation: cause I am smart thats why

4 0

3 years ago

Read 2 more answers

An 75-kg hiker climbs to the summit of Mount Mitchell in western North Carolina. During one 2.0-h period, the climber's vertical

Ostrovityanka [42]

Answer:

The change in gravitational potential energy of the climber-Earth system is $\Delta PE = 396900 \ J$

Explanation:

From the question we are told that

The mass of the hiker is $m = 75 \ kg$

The time taken is $T = 2 \ hr = 2 * 3600 = 7200 \ s$

The vertical elevation after time T is $H = 540 \ m$

The change in gravitational potential is mathematically represented as

$\Delta PE = mgH$

here g is the acceleration due to gravity with value $g = 9.8 \ m/s^2$

substituting values

$\Delta PE = 75 * 9.8 * 540$

$\Delta PE = 396900 \ J$

3 0

3 years ago

Calculate the density of a tin of mass 100g whose dimensions are 2cmx5cmx

Luda [366]

Answer:

your question in not complete.

you need to the high too.

7 0

2 years ago

If the net force on a block is zero

amm1812

If the net force on a block is zero, the block will move at constant velocity

Explanation:

We can answer this question by applying Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:

$\sum F = ma$ (1)

where

$\sum F$ is the net force on the object

m is its mass

a is its acceleration

In this problem, we have a block, and the net force on it is zero:

$\sum F = 0$

According to eq.(1), this also implies that

$a=0$

So, the acceleration of the block is zero.

However, acceleration is the rate of change of velocity of a body:

$a=\frac{\Delta v}{\Delta t}$

where $\Delta v$ is the change in velocity in a time of $\Delta t$ . Since the acceleration is zero, this means that $\Delta v=0$ , and therefore the velocity of the object is constant.