Answer:
B. 7.07 m/s
Explanation:
The velocity of the stone when it leaves the circular path is its tangential velocity, 
, which is given by
where 
is the angular speed and 
is the radius of the circular path.
is given by
where 
is the frequency of revolution.
Thus
Using values from the question,
<em>Note the conversion of 75 cm to 0.75 m</em>
This is because of the conservation of angular momentum, which allows most planets to spin in the same direction, but Venus and Uranus have seem to ignore this as they spin in different directions, as Venus spins clockwise and Uranus is on its side
Answer:
When the ball hits the ground, its velocity is -128 ft/s.
Explanation:
Hi there!
First, let's find the time it takes the ball to reach the ground (the value of t for which s(t) = 0):
s(t) = -16t² + 32t + 240
0 = -16t² + 32t + 240
Solving the quadratic equation with the quadratic formula:
t = 5.0 s (the other solution of the equation is rejected because it is negative).
Now, we have to find the velocity of the ball at t = 5.0 s.
The velocity of the ball is the change of height over time (the derivative of s(t)):
v = ds/dt = s'(t) = -32t + 32
at t = 5.0 s:
s'(5.0) = -32(5.0) + 32 = -128 ft/s
When the ball hits the ground, its velocity is -128 ft/s.
Answer:
The magnifying power of this telescope is (-60).
Explanation:
Given that,
The focal length of the objective lens of an astronomical telescope, 
The focal length of the eyepiece lens of an astronomical telescope, 
To find,
The magnifying power of this telescope.
Solution,
The ratio of focal length of the objective lens to the focal length of the eyepiece lens is called magnifying of the lens. It is given by :
m = -60
So, the magnifying power of this telescope is 60. Therefore, this is the required solution.
Answer:
Kultural na Pamayanan sa Luzon
*Ifugao
*Kalinga
*Gaddang
Explanation:
Sana makatulong po sa inyu...
I tried to answered it...
Pero your welcome in advance..
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