All categories

3 years ago

Is Himalayan mountain still forming today? Explain plzzzz:/

2 answers:

7 0

The continued growth in the Himalayas is likely due to the Indian tectonic plate stillmoving slowly but surely northward. We know the plate is still moving in part because of the frequent earthquakes in the region

KengaRu [80]3 years ago

3 0

Yes, because the tectonic plates are still moving and the mountain is still getting bigger.

You might be interested in

Bao + ........ --> BaCO3 + ......

scoray [572]

Explanation:

Bao + .....Co2... --> BaCO3 + ......

6 0

3 years ago

Between magnesium and calcium, which has the highest ionization energy, and why?

quester [9]

Answer:

magnesium

Explanation:

magnesium has fewer valence shells meaning that the protons have a stronger hold on the electrons and it would take more energy to remove an electron to create an ion.

3 0

3 years ago

Since electrons ___ each other, electrons pairs will be as _____ apart as possible

ELEN [110]

We have to answer based on basic concept on electron.

The correct answer is: Since electrons repel each other, electrons pairs will be as far apart as possible.

We know, electrons are negatively charged particles and negatively charged particles repel to each other.

When electrons which are of similar charge repel each other, they go far apart from each other..

4 0

3 years ago

Which of the following is NOT a way that thermal energy is transferred?

g100num [7]

Answer:

Your answer would be D.) Convection. I hope this helps you! :)

3 0

2 years ago

2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)

Ket [755]

Answer:- 10 L of ethane.

Solution:- The given balanced equation is:

$2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)$

From this equation, ethane and oxygen react in 2:7 mol ratio, the ratio of volumes would also be same if they are at same temperature and pressure.

Since 14 L of each gas are taken, the oxygen will be the limiting reactant and ethane will be the excess reactant. Let's calculate the volume of ethane used:

$14LO_2(\frac{2LC_2H_6}{7LO_2})$

= $4LC_2H_6$

From above calculations, 4 L of ethane are used. So, excess volume of ethane left after the completion of reaction = 14 L - 4 L = 10 L

Hence, 10 L of ethane will be remaining.

5 0

3 years ago