1+3+3+4+6+9+9 is 35
7 numbers so divide by 7
35/7 = 5
Mean is 5
The area of a circular sector of central angle α (in radians) in a circle of radius r is given by
... A = (1/2)r²×(α - sin(α))
Your area is expected to be computed as the sum of the areas of a sector with angle π/3 in a circle of radius 8 and a sector with angle π/2 in a circle of radius 6.
... A = (1/2)8²×(π/3 - sin(π/3)) + (1/2)6²×(π/2 - sin(π/2))
... A ≈ 16.07
Radii are in inches so the units of area will be in². The appropriate choice is
... 16.10 in²
_____
It should be noted that the geometry described is impossible. Chord CD of circle A will have length 6√2 ≈ 8.4853 inches. Chord CD of circle B will have length 8 inches. They cannot both be the same chord.
Answer: 1)
2) 55 points
Step-by-step explanation:
1) A= 8w + 18, w=1.25
A = 8(1.25) + 18
A = 10 + 18
A = 28ft^2
2) 25 points to start with, additional 5 points per magazine they sell, m = number of magazines they sell
total points = 25 + 5m
How many if they sell 6?
total = 25 + 5(6)
= 25 + 30
total = 55
Answer:
Part a) Rectangle
Part b) Triangle
Step-by-step explanation:
<u><em>The picture of the question in the attached figure N 1</em></u>
Part A) A cross section of the rectangular pyramid is cut with a plane parallel to the base. What is the name of the shape created by the cross section?
we know that
When a geometric plane slices any right pyramid so that the cut is parallel to the plane of the base, the cross section will have the same shape (but not the same size) as the base, So, in the case of a right rectangular pyramid, the cross section is a rectangle
Part b) If a cross section of the rectangular pyramid is cut perpendicular to the base, passing through the top vertex, what would be the shape of the resulting cross section?
we know that
Cross sections perpendicular to the base and through the vertex will be triangles
see the attached figure N 2 to better understand the problem