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leva [86]
3 years ago
8

An aircraft flew 5 hours with the wind . The return trip took 6 hours against the wind . If the speed of the plane in still air

is 490 miles per hours more than the speed of the wind , find the wind speed and the speed of the plane in still air
Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0

Answer:

The speed of the plane in still air is 89.83 mph and the speed of air is 8.17 mph.

Step-by-step explanation:

Let the speed of the plane in still air is u mph and the speed of the wind is v mph.

Now, the aircraft flew 490 miles in 5 hours with the wind.  

Hence, u + v = \frac{490}{5} = 98 ........ (1)

Now, the aircraft flew 490 miles in 6 hours against the wind.

So, u - v = \frac{490}{6} = 81.67 ............ (2)

Now, adding equations (1) and (2) we get,

2u = 179.67

⇒ u = 89.83 mph

Now, from equation (1) we get,

v = 98 - u = 98 - 89.83 = 8.17 mph.

Therefore, the speed of the plane in still air is 89.83 mph and the speed of air is 8.17 mph. (Answer)

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504

Step-by-step explanation:

So, lets calculator this.

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Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
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Answer:

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Step-by-step explanation:

Given,

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Thus, probability that a randomly selected person is not color blind,

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What needs to be corrected in this construction of a line parallel to AB passing through C?
monitta

Answer;

C) The second arc should be centered at C.

Explanation;

Assuming the goal is to construct a line parallel to AB that passes through given point C.

-Draw a line through C and across AB at an angle creating D.

- With the compass width about half of DC, and center D, draw the first arc to cross both lines.

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