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Alex787 [66]
4 years ago
15

I’m confused someone explain please

Mathematics
1 answer:
Naya [18.7K]4 years ago
3 0

Answer:

3(x - 12)(x + 2)

Step-by-step explanation:

Given

3x² - 30x - 72 ← factor out 3 from each term

= 3(x² - 10x - 24) ← factor the quadratic

Consider the factors of the constant term (- 24) which sum to give the coefficient of the x- term (- 10)

The factors are - 12 and + 2 , since

- 12 × 2 = - 24 and - 12 + 2 = - 10 , thus

x² - 10x - 24 = (x - 12)(x + 2) and

3x² - 30x - 72 = 3(x - 12)(x + 2)

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6. A ship is on the surface of the water, and its radar detects a submarine at a distance of
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Answer:

the submarine is 92.994 feet ≈ 93 feet deep from the surface of the water

Step-by-step explanation:

We can think in a triangle where the hypotenuse is the detection distance and the angle with the horizontal surface of water is the depression angle, then the underwater distance is the vertical side of the triangle.

If we denote Ф  as the angle of depression ,d as the detection distance and x as the unknown depth of the submarine, using trigonometry:

x = d* sin Ф

thus

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3 years ago
Have someone who can can help me with this I need help
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Answer is underlined

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You have a function that takes in an X value and produces a Y value. The x value equals 5 times the y value, plus 3 more. What's
MissTica

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Step-by-step explanation:

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An equipment rental company charges a flat rate of $25, plus $13 per day for insurance. Kyle has $121. Write an inequality to re
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The temperature of a patient during an illness is given by the function T = -0.1d2 + 1.2d + 98.2 where T = the patient's tempera
Marrrta [24]

Answer:

a) The highest temperature was registered on the sixth day after the onset of the illness.

b) The highest temperature of the patient is 101.8.

Step-by-step explanation:

Let T = -0.1\cdot d^{2}+1.2\cdot d +98.2, we can find the maximum and minimum temperature of the patient by means of the First and Second Derivative Tests, whose procedure is described below:

First Derivative Test

T' = -0.2\cdot d +1.2

-0.2\cdot d +1.2 = 0

d = 6

Second Derivative Test

T'' = -0.2

Which means that critical value found in the previous step is an absolute maximum and there is no absolute minimum.

a) The highest temperature was registered on the sixth day after the onset of the illness.

b) We evaluated the function at critical value found by First Derivative Test:

T (6) = -0.1\cdot (6)^{2}+1.2\cdot (6) +98.2

T(6) = 101.8

The highest temperature of the patient is 101.8.

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3 years ago
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