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REY [17]
2 years ago
5

A mixture of water and graphite is heated to 600 k in a 1 l container. when the system comes to equilibrium it contains 0.15 mol

of h2, 0.15 mol of co, 0.57 mol of h2o, and some graphite. some o2 is added to the system and a spark is applied so that the h2 reacts completely with the o2.
Chemistry
1 answer:
Lunna [17]2 years ago
8 0
(missing in Q) : Calculate the concentration of CO & H2 & H2O when the system returns the equilibrium???

when the reaction equation is:

C(s) + H2O(g)  ↔ H2(g) + CO(g) 

∴ Kc = [H2] [CO] / [H2O]

and we have Kc = 0.0393 (given missing in the question)

when the O2 is added so, the reaction will be:

2H2(g) + O2(g) → 2H2O(g)

that means that 0.15 mol H2 gives 0.15 mol of H2O

∴ by using ICE table:

            [H2O]          [H2]        [CO]

initial 0.57 + 0.15      0               0.15

change  -X                +X              +X

Equ   (0.72-X)             X            (0.15+X)

by substitution:

0.0393 = X (0.15+X) / (0.72-X)  by solving for X

∴ X = 0.098 

∴[H2] = X = 0.098 M

∴[CO] = 0.15 + X
 
           = 0.15 + 0.098 = 0.248 M

∴[H2O] = 0.72 - X

             = 0.72 - 0.098

             = 0.622 M


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Let's plug in the values in the formula:

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On cross multiply:

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3 years ago
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5 0
2 years ago
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Explanation :

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\text{Moles of }Pb(NO_3)_2=\text{Concentration of }Pb(NO_3)_2\times \text{Volume of solution}

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From the balanced chemical reaction we conclude that,

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Now we have to calculate the volume of NH_4I

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Now we have to calculate the moles of PbI_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react to give 1 moles of PbI_2

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Thus, the number of moles of PbI_2 formed from the reaction is, 0.662 moles.

7 0
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