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iVinArrow [24]
3 years ago
6

PLZZZZZ help ASAP!!!!!!! THANK YOU. :) i need all 3 and thank you again!

Chemistry
2 answers:
Allisa [31]3 years ago
8 0
A.Transform
B.Divergent
C. Convergent
nasty-shy [4]3 years ago
3 0
I agree with the person on top have a beautiful day :)
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Which of the following is the name of the process scientists use to gain
kobusy [5.1K]

Scientific method

Explanation:

The scientific method is the name of the process scientists use to gain knowledge about the physical world.

The scientific method is a systematic approach into the study of nature. It follows the following processes:

  • Detailed observation
  • Asking of question
  • Formulation of hypothesis
  • Experimentation
  • Analysis and interpretation
  • Conclusion

learn more:

Experiment brainly.com/question/1621519

#learnwithBrainly

8 0
3 years ago
What pressure is required to compress 156.0 liters of air at 2.00 atmosphere into a cylinder
garik1379 [7]

Answer:

option B.

Explanation:

Given,

V₁ = 156 L

P₁ =2 atm

Now, in the cylinder

P₂ = ?

V₂ = 36

Using relation between pressure and volume

\dfrac{P_1}{V_2}=\dfrac{P_2}{V_1}

\dfrac{2}{36}=\dfrac{P_2}{156}

P_2 = 8.67\ atm

Hence,  pressure is equal to 8.67 atm.

Hence, the correct answer is option B.

7 0
3 years ago
In the following reaction, 451.4 g of lead reacts with excess oxygen forming 365.0 g of lead(II) oxide. Calculate the percent yi
user100 [1]
Let MM(x) be the molar mass of x.

MM(Pb) : MM(PbO)
=207.21 : 223.20  =  451.4 g : x g

cross multiply and solve for x
x=223.2/207.21*451.4
= 486.23 g

Percentage yield = 365.0/486.23= 0.75067 = 75.07% (rounded to 4 sign. fig.)

4 0
3 years ago
Predict the electronegativity of the yet undiscovered element with Z = 119.
Lera25 [3.4K]
We know that the element Z = 119 would be placed right below the Fr, in the column of the alcaline metals.

We also know that the trend in the electronegativity is to decrease when you go up-down ia group.

The known electronegativities of the elements of this group are:

Li: 0.98
Na: 0.93
K: 0.82
Rb: 0.82
Cs: 0.79
Fr: 0.70

Then the hypotetical element Z = 119 would probably have an electronegativity slightly below 0.70, for sure in the range 0.60 - 0.70.



4 0
3 years ago
In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for
inessss [21]

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)

Reduction at cathode :

Cu^+(aq)+2e^-\rightarrow Cu(s)

Reduction potential of  Cu^{2+} to Cu=E^o_{1}=0.34 V

Oxidation at anode:

Fe(s)\rightarrow Fe^{2+}(aq)+2e^-

Reduction potential of  Fe^{2+} to Fe=E^o_{2}=-0.44 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=0.34V -(-0.44 V)=0.78 V

The standard cell potential of the reaction is 0.78 Volts.

3 0
3 years ago
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