<u>Explanation:</u>
s = ? u = 0m/s v = ? a = 5m/s² t = 2s
v = u + at
= 0 + (5 x 2)
= 10 m/s
s = ut + 1/2 at²
= (0)(2) + x
x 5 x 2²
= 10 m
Hope this helps!
The answer is 0.000824653J
You need to use the formula Mass * Velocity^2 over 2
Explanation :
It is given that, the driver accelerates from a stop sign, cruises for 20 s at a constant speed of 60 km/h, and then brakes to come to a stop 40 s after leaving the stop sign.
We know that acceleration is defined as the rate of change of velocity.

Where
dv is the change in velocity, dv = 0 - 60 m/s = -60 m/s
dt is the change in time, dt = 40 s - 30 s = 10 s
So, 

From the graph it is clear that, from 30 s to 40 s the car is decelerating. So, at every second within this time the value of acceleration will be same i.e.
.
High school???
No way
It's work.
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