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3 years ago

6

Reto: Aníbal desea construir una carpa de base hexagonal de 1,40 m de altura. El vértice de la base es de 0,80m y la longitud de

la arista lateral mide 1,80m. ¿cuanto de tela necesito para cubrir la superficie lateral de la carpa? ¿cuanto de tela necesito para cubrir la base de la pirámide, que es un hexágono regular? Cuál es el volumen de la pirámide? ¿cuál es el área total de la pirámide?

1 answer:

Rudiy273 years ago

3 0

Answer:

1.- para cubrir la superficie lateral 4.32 metros²

2.- Area de la base 2.15 metros²

3.- Volumen 1 m³

4.- Area total 6.47 metros²

Explanation:

El área lateral sera calcular el area de seis triangulos iguales cuya base es

0.80 de base x 6 lados = 4.80 metros perimetro de la base

4.80 perimetro de base x 1.80 arista lateral / 2 = 4.32m2

Area de la base:

Perímetro x Apotema / 2

Siendo la Apotema la altura de los triangulos que componen un hexagono calculada utilizando el teorema de pitágoras:

$\sqrt{0.8^2 + (0.8/2)^2} = Apotema$

Apotema = 0.894427191

Area: 4.80 x 0.894427191 / 2 = 2.146625258

sumando el area de la base mas el area lateral se obtiene el area total

2.15 + 4.32 = 6.47 metros

Volumen de la pirámide:

Area de la Base x Altura / 3

2.15 x 1.40 / 3 = 1.00333 m3

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3 years ago

The vacuum pressure of a condenser is given to be 80 kpa. if the atmospheric pressure is 98 kpa, what is the gage pressure and a

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3 years ago

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