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2 years ago

18 less than the quotient of a number and -5 is greater than 3

Mathematics

1 answer:

Amanda [17]2 years ago

4 0

Step-by-step explanation:

x = "a number"

x/-5 - 18 > 3

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(Will give brainliest) Is my answer correct?? If not please correct me

Yuki888 [10]

Hey!

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Answer:

(-6, 2) and (-7, -1) and (0, 0)

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Explanation:

You reflected the triangle. You needed to translate the triangle.

y + 6 is to move up 6 units along the y-axis.

x - 5 is to move left 5 units along the x-axis.

Another thing, the question doesn't state was transformation to use so we are going to assume we are translating.

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Hope This Helped! Good Luck!

5 0

3 years ago

15 POINTS BRAINLIEST

Irina-Kira [14]

Answer:

see explanation

Step-by-step explanation:

g(x) - f(x)

x - 3 - (3x + 2) ← distribute parenthesis by - 1

= x - 3 - 3x - 2 ← collect like terms

= - 2x - 5

There are no restrictions on the domain of - 2x - 5, thus

domain is all real numbers

8 0

3 years ago

92÷9−5=913 find value of p

Vlad [161]

Answer:

which p? there isn't any p in above equation

3 0

2 years ago

The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

which is equal to 0.01

Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

3 0

3 years ago

Which transformations will map octagon PQRSTVWZ onto itself?

Usimov [2.4K]

Answer:

Rotation, Reflection and Translation.

4 0

2 years ago