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kompoz [17]
3 years ago
9

Can you please help me on this question 6(1-4r)+3r=-3(3r-2)-6r

Mathematics
1 answer:
Lisa [10]3 years ago
8 0

Answer:

r=0

Step-by-step explanation:

1. Remove Parentheses

2. Cancel equal terms

3. Collect like terms

4. Move variable to the left

5. Collect like terms

6. Divide both sides by -6

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Simplify the expressions and evaluate for (i) y = -2, (ii) y = 3.<br> 3y (2y-7) - 3 (y - 4) - 63
Diano4ka-milaya [45]

Simplified expression is 6y² - 24y - 51. Value for y=-2 is 21 and value for y=3 is  -69.

Step-by-step explanation:

  • Step 1: Given expression is 3y(2y-7) - 3(y - 4) - 63. Simplify it.

⇒ 6y² - 21y - 3y + 12 - 63

⇒ 6y² - 24y - 51

  • Step 2: Find value of the expression for y = -2

⇒ 6y² - 24y - 51 = 6(-2)² - 24(-2) - 51 = 24 + 48 - 51 = 21

  • Step 3: Find value of the expression for y = 3

⇒ ⇒ 6y² - 24y - 51 = 6(3)² - 24(3) - 51 = 54 - 72 - 51 = -69

8 0
4 years ago
The Niagara Falls ferris wheel has a diameter of 48 meters, and one revolution takes 2.25 minutes to complete. Riders can see Ni
Yanka [14]

The time intervals when the riders could see Niagara falls are; 0.834 < t < 1.416 and (3.084, 3.666)

<h3>How to interpret Cycle Graphs?</h3>

From the diagram attached, we can say that;

Period = 2π/k

where;

k = 2π/2.25

k = 8π/9

Thus;

h(t) = -(48/2) cos (8π/9)t + ((48/2) + 0.5)

h(t) = -24cos (8π/9)t + 24.5

Riders can see Niagara falls if they are higher than 41 meters above the ground. Thus;

41 = -24cos (8π/9)t + 24.5

41 - 24.5 = -24cos (8π/9)t

16.5 = -24cos (8π/9)t

-0.6875 = cos (8π/9)t

cos⁻¹0.6875 = (8π/9)t

t = 0.834 min

Thus, time interval is between;

0.834 < t < (2.25 - 0.834)

⇒ 0.834 < t < 1.416 and

(2.25 + 0.834) < t < (2.25 + 1.416)

⇒ (3.084, 3.666)

Read more about Cycle Graphs at; brainly.com/question/24461724

#SPJ1

4 0
2 years ago
2{ 3[9 + 4(7 -5) - 4]}
Oliga [24]

Answer:

2{3[9+4(7-5)-4]}

2{3[9+4(2)-4]}

2{3[13(2)-4]}

2{3[26-4]}

2{3[22]}

2{66}

132

Step-by-step explanation:

8 0
3 years ago
I really need help quick
Natali [406]

Answer:

\sf x=2+\sqrt{6},\:x=2-\sqrt{6}

Explanation:

\sf y = x^2 -4x

given that y = 2

\sf x^2 -4x = 2

\sf x^2 -4x -2 = 0

using quadratic formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \    \ \ when  \   ax^2 + bx + c = 0

\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}

\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}

\rightarrow \sf x=2+\sqrt{6},\:x=2-\sqrt{6}

in decimals:

\rightarrow \sf x=4.45 , \ -0.45

5 0
2 years ago
Which of the following is equal to7 1/4?
Ivenika [448]

Answer:

B. \sqrt[4]{7}

{7}^{ \frac{1}{4} }  =  \sqrt[4]{7}

5 0
3 years ago
Read 2 more answers
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