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2 years ago

Suppose the collision speed is 20 mph and the rebound speed is 5 mph. The energy ratio is?

Physics

1 answer:

kumpel [21]2 years ago

3 0

Answer:

The energy ratio is $16:1.$

Explanation:

The kinetic energy of the 20mph object is

$K_1 = \dfrac{1}{2}m(20mph)^2$ ,

and the kinetic of the same abject at 5mph is

$K_2 = \dfrac{1}{2}m(5mph)^2;$

therefore, the ratio of $K_1$ to $K_2$ is

$\frac{K_1}{K_2} = \frac{\dfrac{1}{2}m(20mph)^2}{ \dfrac{1}{2}m(5mph)^2} = \frac{(20mph)^2}{(5mph)^2} =\frac{16}{1}$

Thus, the energy ratio is $K_1:K_2 = 16:1$ .

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A car with a mass of 1380 Kg is traveling at 23 m/s to the north. A truck with a mass of 1625 Kg is traveling at 26 m/s to the s

trasher [3.6K]

Answer: -3.49 m/s (to the south)

Explanation:

This problem can be solved by the Conservation of Momentum principle which establishes the initial momentum $p_{i}$ must be equal to the final momentum $p_{f}$ , and taking into account this is aninelastic collision:

Before the collision:

$p_{i}=mV_{o}+MU_{o}$ (1)

After the collision:

$p_{f}=(m+M)V_{f}$ (2)

Where:

$m=1380 kg$ is the mass of the car

$V_{o}=23 m/s$ is the velocity of the car, directed to the north

$M=1625 kg$ is the mass of the truck

$U_{o}=-26 m/s$ is the velocity of the truck, directed to the south

$V_{f}$ is the final velocity of both the car and the truck

$p_{i}=p_{f}$ (3)

$mV_{o}+MU_{o}=(m+M)V_{f}$ (4)

Isolating $V_{f}$ :

$V_{f}=\frac{mV_{o}+MU_{o}}{m+M}$ (5)

$V_{f}=\frac{(1380 kg)(23 m/s)+(1625 kg)(-26 m/s)}{1380 kg+1625 kg}$ (6)

Finally:

$V_{f}=-3.49 m/s$ The negative sign indicates the direction of the velocity is to the south

8 0

3 years ago

Hello please help me out

agasfer [191]

The answer is c.........

8 0

2 years ago

Read 2 more answers

A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts

expeople1 [14]

A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts moving the ball moves toward the back of the train. This happened due to inertia

An object at rest remains at rest, or if in motion, remains in motion unless a net external force acts on it .

When a train starts moving forward, the ball placed on the floor tends to fall backward is an example of inertia of rest. Due to the reason that the lower part of the ball is in contact with the surface and rest of the part is not . As the train starts moving, its lower part gets the motion as the floor starts moving but the upper part will remain as it is as it is not in contact with the floor , hence do not attain any motion due to the inertia of rest simultaneously i.e. it tends to remain at the same place.

To learn more about inertia here :

brainly.com/question/11049261

#SPJ1

8 0

1 year ago

If the mass of a material is 111 grams and the volume of the material is 23 cm3, what would the density of the material be? g/cm

Butoxors [25]

Density can be kg/m^3 or g/cm3
In g/cm3 density =mass /volume =111g/23cm3
=4.826g/cm3.

In kg/m3,density=mass/volume. converting mass in grams to kg, 1000g=1kg,111g=0.111kg.
cm3 to m3, 1cm3=10^-6m3, 23cm3=0.000023m3
density=0.111kg/0.000023m3 or 2.3*10^-5=4,826.1kg/m3.

the other is a long process.

4 0

3 years ago

A man lifts a 25.9 kg bucket from a well and does 5.92 kJ of work.The acceleration of gravity is 9.8 m/s^2 . How deep is the wel

Jet001 [13]

Answer:

The well is 23.3 m

Explanation:

As the bucket is lifted out of the well, energy in the man is being transferred to the bucket as gravitational potential energy.

Work done against gravity = mass * height * acceleration due to to gravity

W = mgh

5 920 J = 25.9 kg * h * 9.8 m/s²

h = 23.3 m

4 0

2 years ago