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3 years ago

Suppose the collision speed is 20 mph and the rebound speed is 5 mph. The energy ratio is?

Physics

1 answer:

kumpel [21]3 years ago

3 0

Answer:

The energy ratio is $16:1.$

Explanation:

The kinetic energy of the 20mph object is

$K_1 = \dfrac{1}{2}m(20mph)^2$ ,

and the kinetic of the same abject at 5mph is

$K_2 = \dfrac{1}{2}m(5mph)^2;$

therefore, the ratio of $K_1$ to $K_2$ is

$\frac{K_1}{K_2} = \frac{\dfrac{1}{2}m(20mph)^2}{ \dfrac{1}{2}m(5mph)^2} = \frac{(20mph)^2}{(5mph)^2} =\frac{16}{1}$

Thus, the energy ratio is $K_1:K_2 = 16:1$ .

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Your fitness tracker tells you that you have delivered 124 kJ of work during your workout. The tracker also shows that you have

REY [17]

To solve this problem, we must basically count the total energy lost converting all the values given in the international system.

The energy loss is given by both 124KJ and 124food heats.

Since the energy conversion we know that 1 food calories is equal to 4,184J. So:

$124 calories (\frac{4.184J}{1 calories}) = 518.816J = 0.518816kJ$

Therefore the total energy lost will be

$E_{lost} = 124 KJ + 0.518816 KJ$

$E_{lost} = 124.518KJ$

Therefore the total energy lost to the surroindings in form of heat is 124.518kJ

3 0

3 years ago

Monochromatic light is incident on a pair of slits that are separated by 0.220 mm. The screen is 2.60 m away from the slits. (As

Naddik [55]

Answer:

$\lambda = 1.667 nm$

$\theta = 0.8681^o$

Explanation:

From the question we are told that

The distance of separation is $d = 0.220 \ mm = 0.00022 \ m$

The is distance of the screen from the slit is $D = 2.60 \ m$

The distance between the central bright fringe and either of the adjacent bright $y = 1.97 cm = 1.97 *10^{-2}\ m$

Generally the condition for constructive interference is

$d sin \tha(\theta ) = n \lambda$

From the question we are told that small-angle approximation is valid here.

So $sin (\theta ) = \theta$

=> $d \theta = n \lambda$

=> $\theta = \frac{n * \lambda }{d }$

Here n is the order of maxima and the value is n = 1 because we are considering the central bright fringe and either of the adjacent bright fringes

Generally the distance between the central bright fringe and either of the adjacent bright is mathematically represented as

$y = D * sin (\theta )$

From the question we are told that small-angle approximation is valid here.

$y = D * \theta$

=> $\theta = \frac{ y}{D}$

$\frac{n * \lambda }{d } = \frac{y}{D}$

$\lambda =\frac{d * y }{n * D}$

substituting values

$\lambda = \frac{0.00022 * 1.97*10^{-2} }{1 * 2.60 }$

$\lambda = 1.667 *10^{-6}$

$\lambda = 1.667 nm$

In the b part of the question we are considering the next set of bright fringe so n= 2

Hence

$dsin (\theta ) = n \lambda$

$\theta = sin^{-1}[\frac{ n * \lambda }{d} ]$

$\theta = sin^{-1}[\frac{ 2 * 1667 *10^{-9}}{ 0.00022} ]$

$\theta = 0.8681^o$

7 0

4 years ago

How does refraction allow thin convex lenses to work?

melomori [17]

Answer:

https://www.khanacademy.org/science/physics/geometric-optics/lenses/v/convex-lenses

Explanation:

Here is a link to a video to tell you about this.

7 0

3 years ago

Read 2 more answers

A bowling ball has a mass of 1.7 The ball leaves a bowler's hand at a speed of 7.0 m/s calculate the kinetic energy of the bowli

Andrews [41]

Answer:

the answer is 41.65 J

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3 years ago

A net force of magnitude 36 N gives an object of mass m1 an acceleration of 6.0 m/s^2. The same net force gives m1 and another o

Jet001 [13]

This is a beautiful problem to test whether a student actually understands
Newton's 2nd law of motion . . . Force = (mass) x (acceleration).

That simple law is all you need to solve this problem, but you need to
use it a few times.

m₁ alone:
   Force = (mass) x (acceleration)

   36 N = ( m₁ ) x (6 m/s²)

   m₁ = (36 N) / (6 m/s²)

   m₁ = 6 kilograms .

m₁ and m₂ glued together:
   Force = (mass) x (acceleration)

   36 N = (6 kg + m₂) x (2 m/s²)

   6 kg + m₂ = (36 N) / (2 m/s²) = 18 kilograms

   m₂ = 12 kilograms .

m₂ alone:
   Force = (mass) x (acceleration)

   36 N = (12 kg) x (acceleration)

   Acceleration = (36 N) / (12 kg)

   Acceleration =   3 m/s²

3 0

4 years ago