The products of a chemical reaction are the substances that are changed and the chemicals on the right side of a chemical equation. The correct options are B and C.
<h3>What is chemical reaction?</h3>
The chemical reaction is the reaction between two reactants which led to the formation of products.
The products are substances which forms after reaction. The reactants are the substances which are original materials.
The reactants lie on the left side and products lie on the right side of the reaction.
Thus, the correct options are B and C.
Learn more about chemical reaction.
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Answer:
The true course:
north of east
The ground speed of the plane: 96.68 m/s
Explanation:
Given:
= velocity of wind = ![30\ km/h\ S45^\circ E = (30\cos 45^\circ\ \hat{i}-30\sin 45^\circ\ \hat{j})\ km/h = (21.21\ \hat{i}-21.21\ \hat{j})\ km/h](https://tex.z-dn.net/?f=30%5C%20km%2Fh%5C%20S45%5E%5Ccirc%20E%20%3D%20%2830%5Ccos%2045%5E%5Ccirc%5C%20%5Chat%7Bi%7D-30%5Csin%2045%5E%5Ccirc%5C%20%5Chat%7Bj%7D%29%5C%20km%2Fh%20%3D%20%2821.21%5C%20%5Chat%7Bi%7D-21.21%5C%20%5Chat%7Bj%7D%29%5C%20km%2Fh)
= velocity of plane in still air = ![100\ km/h\ N60^\circ E = (100\cos 60^\circ\ \hat{i}+100\sin 60^\circ\ \hat{j})\ km/h = (50\ \hat{i}+86.60\ \hat{j})\ km/h](https://tex.z-dn.net/?f=100%5C%20km%2Fh%5C%20N60%5E%5Ccirc%20E%20%3D%20%28100%5Ccos%2060%5E%5Ccirc%5C%20%5Chat%7Bi%7D%2B100%5Csin%2060%5E%5Ccirc%5C%20%5Chat%7Bj%7D%29%5C%20km%2Fh%20%3D%20%2850%5C%20%5Chat%7Bi%7D%2B86.60%5C%20%5Chat%7Bj%7D%29%5C%20km%2Fh)
Assume:
= resultant velocity of the plane
= direction of the plane with the east
Since the resultant is the vector addition of all the vectors. So, the resultant velocity of the plane will be the vector sum of the wind velocity and the plane velocity in still air.
![\therefore V_r = V_p+V_w\\\Rightarrow V_r = (50\ \hat{i}+86.60\ \hat{j})\ km/h+(21.21\ \hat{i}-21.21\ \hat{j})\ km/h\\\Rightarrow V_r = (71.21\ \hat{i}+65.39\ \hat{j})\ km/h](https://tex.z-dn.net/?f=%5Ctherefore%20V_r%20%3D%20V_p%2BV_w%5C%5C%5CRightarrow%20V_r%20%3D%20%2850%5C%20%5Chat%7Bi%7D%2B86.60%5C%20%5Chat%7Bj%7D%29%5C%20km%2Fh%2B%2821.21%5C%20%5Chat%7Bi%7D-21.21%5C%20%5Chat%7Bj%7D%29%5C%20km%2Fh%5C%5C%5CRightarrow%20V_r%20%3D%20%2871.21%5C%20%5Chat%7Bi%7D%2B65.39%5C%20%5Chat%7Bj%7D%29%5C%20km%2Fh)
Let us find the direction of this resultant velocity with respect to east direction:
![\theta = \tan^{-1}(\dfrac{65.39}{71.21})\\\Rightarrow \theta = 40.29^\circ](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Ctan%5E%7B-1%7D%28%5Cdfrac%7B65.39%7D%7B71.21%7D%29%5C%5C%5CRightarrow%20%5Ctheta%20%3D%2040.29%5E%5Ccirc)
This means the the true course of the plane is in the direction of
north of east.
The ground speed will be the magnitude of the resultant velocity of the plane.
![\therefore Magnitude = \sqrt{71.21^2+65.39^2} = 96.68\ km/h](https://tex.z-dn.net/?f=%5Ctherefore%20Magnitude%20%3D%20%5Csqrt%7B71.21%5E2%2B65.39%5E2%7D%20%3D%2096.68%5C%20km%2Fh)
Hence, the ground speed of the plane is 96.68 km/h.
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a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2
<span>= 2.40 x 10-3 N
b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
Answer:
Sorry I don't understand this language I'm sorry