Answer: After fusing helium in its core to carbon, the Sun will begin to collapse again, evolving into a compact white dwarf star after ejecting its outer atmosphere as a planetary nebula. The predicted final mass is 54.1% of the present value, most likely consisting primarily of carbon and oxygen.
Answer:
P =18760.5 Pa
Explanation:
Given that
Volume ,V= 0.0434 m³
Mass ,m= 4.19 g = 0.00419 kg
T= 417 K
If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation
Ideal gas equation P V = m R T
p=Pressure ,V = Volume ,m =mass
T=Temperature ,R=Universal gas constant
Now by putting the values
P V = m R T
For water R= 0.466 KJ/kgK
P x 0.0434 = 0.00419 x 0.466 x 417
P =18.7605 KPa
P =18760.5 Pa
Therefore the answer is 18760.5 Pa
Your finger becomes negatively charged - d.
X-ray formation
Energy difference in the first ionization of the same group of elements
Differential linear emission spectra of different elements
Explanation:
The formation of x-ray, energy difference in the first ionization of the same group of elements and differential linear emission spectra of different elements can be justified by the Bohr model of the atom.
- According to Neil Bohr, in an atom, the extranuclear part consists of electrons in specific spherical orbits around the nucleus.
- Bohr's model explained the discrete lines in atomic spectrum of different elements.
- Due to excitation of electrons, some rays are given off. Some of these are energetic like x-rays.
- The energy difference between the first ionization of the same group of elements is a proof that electrons are in specific spherical orbits.
- The higher the energy the level, the ease at which electrons can be removed and the lower the ionization energy.
Learn more:
Bohr model of the atom brainly.com/question/4986277
#learnwithBrainly
Given:
F = ax
where
x = distance by which the rubber band is stretched
a = constant
The work done in stretching the rubber band from x = 0 to x = L is
![W=\int_{0}^{L} Fdx = \int_{0}^{L}ax \, dx = \frac{a}{2} [x^{2} ]_{0}^{L} = \frac{aL^{2}}{2}](https://tex.z-dn.net/?f=W%3D%5Cint_%7B0%7D%5E%7BL%7D%20Fdx%20%3D%20%5Cint_%7B0%7D%5E%7BL%7Dax%20%5C%2C%20dx%20%3D%20%5Cfrac%7Ba%7D%7B2%7D%20%20%5Bx%5E%7B2%7D%20%5D_%7B0%7D%5E%7BL%7D%20%3D%20%20%5Cfrac%7BaL%5E%7B2%7D%7D%7B2%7D%20)
Answer:
