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Maslowich
4 years ago
12

Starting from Joe's Gas Station, a car travels due north on Avenue A for 2.4 mi, then turns right and travels on Cedar Street fo

r 1.0 mi, and then turns right again and travels on Washington Avenue for 0.6 mi.
How far is the car from Joe's Gas Station?

Physics
1 answer:
Bumek [7]4 years ago
7 0

Answer:2.05 mi

Explanation:

Given

Joe travel 2.4 mi due to north

r_1=2.4\hat{j}

then turns right and travel 1 mi

r_{21}=1\hat{i}

then it again turn right on Washington avenue

r_{32}=-0.6\hat{j}

Final Position of Joe is

r_3=\hat{i}+1.8\hat{j}

its distance from gas station is

|r_{3}|=\sqrt{1^2+1.8^2}

=2.059 mi[/tex]

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Answer:

Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.

Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.

So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:

At,

t=0, v=0 m/s

t=1, v=0+10 m/s;

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