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alexandr402 [8]
3 years ago
11

If an object accelerates from rest, with a constant of 8 m/s2, what will its velocity be after 35s?

Physics
1 answer:
AlladinOne [14]3 years ago
5 0

Answer:

<em>Its speed will be 280 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:

v_f=v_o+at

The object accelerates from rest (vo=0) at a constant acceleration of a=8\ m/s^2. The final speed at t=35 seconds is:

v_f=0+8*35

v_f=280\ m/s

Its speed will be 280 m/s

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An instrument is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/
Katen [24]
<h2>Answer: 12 s</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told <u>the instrument is thrown upward</u> from the surface, we will only use the equations related to the Y axis.

In this sense, the main movement equation in the Y axis is:

y-y_{o}=V_{o}.t-\frac{1}{2}g.t^{2}    (1)

Where:

y  is the instrument's final position  

y_{o}=0  is the instrument's initial position

V_{o}=15m/s is the instrument's initial velocity

t is the time the parabolic movement lasts

g=2.5\frac{m}{s^{2}}  is the acceleration due to gravity at the surface of planet X.

As we know y_{o}=0  and y=0 when the object hits the ground, equation (1) is rewritten as:

0=V_{o}.t-\frac{1}{2}g.t^{2}    (2)

Finding t:

0=t(V_{o}-\frac{1}{2}g.t^{2})   (3)

t=\frac{2V_{o}}{g}   (4)

t=\frac{2(15m/s)}{2.5\frac{m}{s^{2}}}   (5)

Finally:

t=12s

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4 years ago
What is happening in the first part of this picture?
d1i1m1o1n [39]

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Explanation:

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What is the speed od sail boat that us traveling 100 meters in 120 seconds?​
Phantasy [73]
The sailboat is about 0.83m/sec (rounded to the nearest tenth).

To find speed, you would calculate distance over time.

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3 years ago
A watermelon is blown into three pieces by a large firecracker. Two pieces of equal mass m fly away perpendicular to one another
laiz [17]

Answer

given,

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V_3 = \dfrac{V}{3}(-\hat{i}-\hat{j})

V_3 = \dfrac{V}{3}\sqrt{1^2+1^2}

V_3 = \dfrac{V}{3}\sqrt{2}

velocity of third component

V_3 = \dfrac{31}{3}\sqrt{2}

V_3 = 14.61\ m/s

angle

\theta = tan^{-1}(\dfrac{-1}{-1})

\theta = tan^{-1}(1)

\theta = 45^0

5 0
4 years ago
What increase in temperature is needed to increase the length of an aluminum meterstick by 1.0 mm?
Fudgin [204]

Answer:

42k

Explanation:

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