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alexandr402 [8]
3 years ago
11

If an object accelerates from rest, with a constant of 8 m/s2, what will its velocity be after 35s?

Physics
1 answer:
AlladinOne [14]3 years ago
5 0

Answer:

<em>Its speed will be 280 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:

v_f=v_o+at

The object accelerates from rest (vo=0) at a constant acceleration of a=8\ m/s^2. The final speed at t=35 seconds is:

v_f=0+8*35

v_f=280\ m/s

Its speed will be 280 m/s

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Answer:

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Answer:

0.37sec

Explanation:

Period of oscillation of a simple pendulum of length L is:

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T = 2 x 3.14 x √[0.54/9.8]

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An oscillating pendulum, or anything else in nature that involves "simple harmonic" (sinusoidal) motion, spends 1/4 of its period going from zero speed to maximum speed, and another 1/4 going from maximum speed to zero speed again, etc. After four quarter-periods it is back where it started.

The ball will first have V(max) at T/4,

=>V(max) = 1.47/4 = 0.37 sec

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Why do you lurch forward in a bus that suddenly slows? why do you lurch backward when it picks up speed? what law applies here?
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