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exis [7]
2 years ago
6

If 20.0 grams of Na reacts with 30.0 gtams of Cl2 what mass of NaCl is produfed by the reaction

Chemistry
1 answer:
IgorLugansk [536]2 years ago
6 0

Answer:

mNaCl = mNa + mCl

mNa = 20g

mCl = mCl2/2 = 30/2 = 15g

mNaCl= 20+15 = 35g

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What is the chemical formula for the compound magnesium perchlorate? Use the list of polyatomic ions and the periodic table to h
8_murik_8 [283]

The chemical formula for the compound magnesium perchlorate is Mg(ClO₄)₂

Magnesium perchlorate or Mg(ClO₄)₂ is an ionic compound.

Perchlorate here is an anion which is represented by ClO₄⁻. Perchlorate is a polyatiomic anion, where one Cl atom is bonded to four O atoms.

The magnesium cation is represented by Mg²⁺

So one Mg²⁺ cation combines with two ClO₄⁻ anion to form one molecule of Mg(ClO₄)₂


6 0
3 years ago
Rusting of iron is a very common chemical reaction. It results in one form from Fe reacting with oxygen gas to produce iron (III
Vlada [557]

<u>Answer:</u> The given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

<u>Explanation:</u>

We are given:

Moles of iron = 12.0 moles

The chemical equation for the rusting of iron follows:

4Fe+3O_2\rightarrow 2Fe_2O_3

  • <u>For oxygen gas:</u>

By Stoichiometry of the reaction:

4 moles of iron reacts with 3 moles of oxygen gas

So, 12.0 moles of iron will react with = \frac{3}{4}\times 12.0=9.0mol of oxygen gas

  • <u>For iron (III) oxide:</u>

By Stoichiometry of the reaction:

4 moles of iron produces 2 moles of iron (III) oxide

So, 12.0 moles of iron will produce = \frac{2}{4}\times 12.0=6.0mol of iron (III) oxide

Hence, the given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

5 0
3 years ago
50 POINTS..!!! NEED RHE ANSWER ASAP..!!! consider the original wave at the top of the illustration. compare the original wave to
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Answer:

my best guess is b

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4 0
3 years ago
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yawa3891 [41]

Explanation:

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a) The full electronic configuration is given as;

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The final electron is placed in the d orbital. The shell is 3d

(b) When scandium has a charge if +1, it has lost an electron. The total number of electrons would now be 21-1 = 20

The electronic configuration would be given as;

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The electron in the 3d orbital would be removed.

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3 years ago
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xeze [42]

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So your answer is no but fake crystals yes

8 0
2 years ago
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