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What mass of cu(s)cu(s) is electroplated by running 14. 5 aa of current through a cu2 (aq)cu2 (aq) solution for 4. 00 hh?

galina1969 [7]

The mass of Copper electroplated is 68.76 g

<h3>What is electroplating?</h3>

The process of plating a metal onto another is known as electroplating.

It is often used to prevent corrosion of metal or for the decorative purposes

In this process, electric current is passed through an aqueous solution containing dissolved cations.

The dissolved cations are reduced developing a thin metal coating on the electrode.

At cathode,

$Cu^{2+}(aq) + 2e^-\rightarrow Cu(s)$

Current, I = 14.5 A

Time, t = 4 hrs = 4×60×60 = 14400 sec

Charge, q = It = 14.5×14400= 208800 C

Copper metal deposited by 2×96487 C = 63.55 g

Copper metal deposited by 208800 C = $\frac{63.55 \times208800}{2\times96487}$

= 68.76g

Hence, The mass of Copper electroplated is 68.76 g

Learn more about electroplating:

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4 0

1 year ago

Read 2 more answers

Protein x has an absorptivity of 0.4 ml·mg-1 ·cm-1 at 280 nm. What is the absorbance at 280 nm of a 2.0 mg ·ml-1 solution of pro

Evgen [1.6K]

Absorbance measures the ability of the substance to absorb light at a specific wavelength.

Absorbance is also equal to the product of molar absorptivity, path length and molar concentration.

The mathematical expression is given as:

$A= \epsilon l c$ (1)

where, A = absorbance

$\epsilon$ = molar absorptivity

l = path length

c = molar concentration.

The above formula is said to Beer's Law.

Absorptivity of protein x = $0.4 mLmg^{-1}cm^{-1}$

Path length = 1 cm

Molar concentration = $2.0 mg mL^{-1}$

Put the values in formula (1)

$Absorbance at 280 nm = 0.4 mL mg^{-1}cm^{-1}\times 1 cm \times 2.0 mg mL^{-1}$

= $0.8$

Thus, absorbance at 280 nm = $0.8$

3 0

3 years ago

An object has a density of 20.00 g/mL. If the object has a volume of 50.00 mL, what is its mass?

LuckyWell [14K]

Answer:

<h3>The answer is 1000 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 50 mL

density = 20 g/mL

We have

mass = 20 × 50

We have the final answer as

Hope this helps you

5 0

3 years ago

in order to make tea, 32,000 J of energy were added to 100.0g of water. what was the temperature Chang of the water?

mina [271]

Answer:

ΔT = 76.5 °C

Explanation:

Given data:

Amount of water = 100.0 g

Energy needed = 32000 J

Change in temperature = ?

Solution,

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = m.c. ΔT

ΔT = Q / m.c

ΔT = 32000 j/ 100.0 g × 4.184 j/g. °C

ΔT = 32000 j / 418.4 j /°C

ΔT = 76.5 °C

5 0

3 years ago

25.0 g of barium hydroxide is dissolved in 120.0g of water. What is the morality?

Vinvika [58]

Molarity: M = #moles of solute / liters of solution

# moles = mass / molar mass

Molar mass calculation

Barium hydroxide = Ba (OH)2

Atomic masses
Ba = 137.4 g/mol
O=16 g/mol
H=1 g/mol
Molar mass of Ba (OH)2 = 137.4 g/mol + 2*16g/mol + 2*1 g/mol = 171.4 g/mol

# mol = 25.0g/171.4 g/mol = 0.146 mol

For the volume of water use the fact that the density is 1g/ml., so 120 g = 120 ml = 0,120 liters.

M = 0.146mol / 0.120 liters = 1.22 mol/liter

3 0

3 years ago