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ElenaW [278]
3 years ago
11

NEED ASAP!!!!

Chemistry
1 answer:
marin [14]3 years ago
8 0

Answer:

A

D

E

and maybe C I'm not sure on that one.

Explanation:

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Plsz do solv this question hpl​
emmasim [6.3K]
We are given the resistance and voltage of this lamp and we are asked to find the current; the equation that relates these together is Ohm’s Law, V = IR. Simply plug and solve:

V = IR
(220 V) = I(484 Ohms)
I = 0.4545 Amps

The lamp has a current of 0.4545 Amps passing through it under these conditions.

Hope this helps!
7 0
3 years ago
A solution that has a relatively large quantity of solute dissolved in the solvent is:? and please explain the answer
seraphim [82]
A solution that has a high amount of solute/concentration in the solvent is concentrated because if there is a lot of solute compared to the solvent, then the ratio of solute to solvent is higher, and thus the concentration is higher too.
Hope this helps!
7 0
3 years ago
Part B Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, Be.
dmitriy555 [2]

<u>Answer:</u> The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

<u>Explanation:</u>

There are 4 quantum numbers:

  • Principal Quantum number (n) specifies the energy of the electron in a shell.
  • Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
  • Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
  • Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of +\frac{1}{2} or -\frac{1}{2}

Berylium (Be) is the 4th element of periodic table having electronic configuration of 1s^22s^2

  • <u>For electrons in 1s-orbital, the quantum numbers can be:</u>

For first electron:

n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}

For second electron:

n=1\\l=0\\m=0\\s=-\frac{1}{2}

  • <u>For electrons in 2s-orbital, the quantum numbers can be:</u>

For first electron:

n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}

For second electron:

n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

4 0
3 years ago
Darwin observed how farmers and breeders produced many kinds of farm animals and plants. These plants and animals had traits tha
NISA [10]

the answer is A......

it is supported by practical evidence and examples. this is the answer because he tried and tested many different ways to see what would happen so he is happy with the conclusion that what he tested is what he gets.

3 0
4 years ago
Read 2 more answers
An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=
xeze [42]

<u>Given:</u>

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

<u>To determine:</u>

the amount of C-14 after 90769076 years

<u>Explanation:</u>

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

where A = concentration of the radioactive species after time t

A₀ = initial concentration

k = decay constant

Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years

3 0
4 years ago
Read 2 more answers
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