Answer: 122 moles
Procedure:
1) Convert all the units to the same unit
2) mass of a penny = 2.50 g
3) mass of the Moon = 7.35 * 10^22 kg (I had to arrage your numbers because it was wrong).
=> 7.35 * 10^22 kg * 1000 g / kg = 7.35 * 10^ 25 g.
4) find how many times the mass of a penny is contained in the mass of the Moon.
You have to divide the mass of the Moon by the mass of a penny
7.35 * 10^ 25 g / 2.50 g = 2.94 * 10^25 pennies
That means that 2.94 * 10^ 25 pennies have the mass of the Moon, which you can check by mulitiplying the mass of one penny times the number ob pennies: 2.50 g * 2.94 * 10^25 = 7.35 * 10^25.
5) Convert the number of pennies into mole unit. That is using Avogadros's number: 6.022 * 10^ 23
7.35 * 10^ 25 penny * 1 mol / (6.022 * 10^ 23 penny) = 1.22* 10^ 2 mole = 122 mol.
Answer: 122 mol
Answer:
The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Answer is: the enthalpy is -4383.2 kJ.
Reaction 1: 2M(s) + 6HCl(aq) → 2MCl₃(aq) + 3H₂(g); ΔrH₁ = -725.0 kJ.
Reaction 2: HCl(g) → HCl(aq); ΔrH₂ = -74.8 kJ.
Reaction 3: H₂(g) + Cl₂(g) → 2HCl(g); ∆rH₃ = -1845.0 kJ.
Reaction 4: MCl₃(s) → MCl₃(aq); ΔrH₄ = -476.0 kJ.
Reaction 5: 2M(s) + 3Cl₂(g) → 2MCl₃(s); ΔrH₅ = ?
Using Hess's law (substances that appear in the left and right side of the first, second, third and fourth reaction must cancel out to get fifth reaction):
ΔrH₅ = ΔrH₁ - 6 · ΔrH₂ + 3 · ΔrH₃ - 3 · ΔrH₄.
ΔrH₅ = -725 kJ - 6 · (-74.8 kJ) + 3 · (-1845 kJ) - 3 · (-476 kJ).
ΔrH₅ = -4383.2 kJ.
Gold isn't very reactive (it's low on the reactivity table).
It doesn't react with oxygen or halogens with any ease, nor does it tend to dissolve in acid.