What determines a molecules VSEPR shape?

1 answer:

3 0

Using the VSEPR theory, the electron bond pairs and lone pairs on the center atom will help us predict the shape of a molecule. The shape of a molecule is determined by the location of the nuclei and its electrons. The electrons and the nuclei settle into positions that minimize repulsion and maximize attraction.

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What is most likely a molecule ina wall-filling material

Alborosie

I believe that would be C6H6, Benzene.
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4 years ago

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What mass in grams of MgSO4 is required to make 59.3 mL of 2.68 M<br> solution?

love history [14]

Answer:

Approximately $19.1\; \rm g$ .

Explanation:

<h3>Number of moles of formula units of magnesium sulfate required to make the solution</h3>

The unit of concentration in this question is " $\rm M$ ". That's equivalent to " $\rm mol \cdot L^{-1}$ " (moles per liter.) In other words:

$c(\mathrm{MgSO_4}) = 2.68\; \rm M = 2.68\; \rm mol \cdot L^{-1}$ .

However, the unit of the volume of this solution is in milliliters. Convert that unit to liters:

$\displaystyle V = 59.3\; \rm mL = 59.3 \; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.0593\; \rm L$ .

Calculate the number of moles of $\rm MgSO_4$ formula units required to make this solution:

$\begin{aligned}n(\rm MgSO_4) &= c \cdot V \\ &= 2.68 \; \rm mol \cdot L^{-1} \times 0.0593\; \rm L \approx 0.159\; \rm mol \end{aligned}$ .

<h3>Mass of magnesium sulfate in the solution</h3>

Look up the relative atomic mass data of $\rm Mg$ , $\rm S$ , and $\rm O$ on a modern periodic table:

$\rm Mg$ : $24.305$ .
$\rm S$ : $\rm 32.06$ .
$\rm O$ : $15.999$ .

Calculate the formula mass of $\rm MgSO_4$ using these values:

$M(\mathrm{MgSO_4}) = 24.305 + 32.06 + 4 \times 15.999 \approx 120.361\; \rm g \cdot mol^{-1}$ .

Using this formula mass, calculate the mass of that (approximately) $0.159\; \rm mol$ of $\rm MgSO_4$ formula units:

$\begin{aligned}m(\mathrm{MgSO_4}) &= n \cdot M \\&\approx 0.159 \; \rm mol \times 120.361 \; \rm g \cdot mol^{-1} \approx 19.1\; \rm g\end{aligned}$ .