B) 40%
The balanced equation indicates that for every 3 moles of H2 used, 2 moles of NH3 will be produced. So the reaction if it had 100% yield would produce (2.00 / 3) * 2 = 1.333333333 moles of NH3. But only 0.54 moles were produced. So the percent yield is 0.54 / 1.3333 = 0.405 = 40.5%. This is a close enough match to option "b" to be considered correct.
First, you need to find the mass of 1 mol of sugar. Mass, or molar mass, can simply be found by adding the masses of the individual elements. These are given to you on the periodic table.
12 x 12.011 grams (molar mass of Carbon) = 144.132 g
22 x 1.008 grams (molar mass of Hydrogen) = 22.176 g
11 x 15.999 grams (molar mass of Oxygen) = 175.989 g
Add all of the pieces together.
144.132 g + 22.176 g + 175.989 g = 342.297 grams
So, if one mole has 342.297 grams, then 7.35 of that amount will be your answer.
342.297 g/mol x 7.35 mol = 2,515.88 grams
B because once the circuit is burned the lights will all go of
Answer:
8.937g/cm³
Explanation:
To answer this question we need to know that, in 1 unit FCC cell you have:
Edge length = √8 * R
<em>Volume = 8√8 * R³</em>
<em>And there are 4 atoms per unit cell</em>
<em />
<em>Mass of 4 atoms in g:</em>
4 atom * (1mol / 6.022x10²³atom) * (63.55g / mol) = 4.221x10⁻²²g
<em />
<em>Volume in cm³:</em>
0.1278nm * (1x10⁻⁷cm / 1nm) = 1.278x10⁻⁸cm
Volume = 8√8 * (1.278x10⁻⁸cm)³
Volume = 4.723x10⁻²³cm³
And density is:
4.221x10⁻²²g / 4.723x10⁻²³cm³ =
<h3>8.937g/cm³</h3>
