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4 years ago

ASAP please 25 points if right

Physics

1 answer:

garik1379 [7]4 years ago

5 0

Answer:

1. The resistance of any physical object to any velocity

2. It continues in it's existing state of rest or uniform motion

3. Mass is a quantity that is solely dependent upon the inertia of an object.

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The earth has about 80 times the mass of the earth's moon. The gravitational force exerted on the moon by the earth has what rel

chubhunter [2.5K]

Answer:

Both forces are the same.

Explanation:

The problem states that:

$m_e = 80*m_m$

The force exerted on the moon by earth is given by:

$F_m=\frac{K*m_e*m_m}{d^2}$ where K is the gravitational constant, and d is the separation distance between the earth and the moon.

The force exerted on the earth by moon is given by:

$F_e=\frac{K*m_m*m_e}{d^2}$ where K is the gravitational constant, and d is the separation distance between the earth and the moon.

The relation is therefore:

$F_m/F_e = \frac{K*m_e*m_m/d^2}{K*m_m*m_e/d^2}=1$

As you can see, they are the same.

4 0

4 years ago

11. Explain why in terms of gravity and air resistance and the 2nd law, objects in free fall regardless of mass hit at the same

Alchen [17]

Answer:

When an object is dropped, it accelerates toward the center of Earth. Newton's second law states that a net force on an object is responsible for its acceleration. If air resistance is negligible, the net force on a falling object is the gravitational force.

7 0

3 years ago

You are doing a measurement to determine the conductance of an artificial membrane. The membrane is selectively permeable to Na

alex41 [277]

Answer:

What is the membrane's conductance = 2.47miuS

Explanation:

The detailed step and appropriate formula is as shown in the attached file.

8 0

3 years ago

System uses 49J of energy to do work in the change of internal energy is 58 j. how much heat was added to the system?

Alika [10]

Answer:

107

Explanation:

6 0

3 years ago

A satellite has a mass of 5850 kg and is in a circular orbit 4.1 x10 to the 5th power m above the surface of a planet. The perio

koban [17]

Answer:

W = 24.28 kN

Explanation:

given,

Mass of satellite = 5850 Kg

height , h = 4.1 x 10⁵ m

Radius of planet = 4.15 x 10⁶ m

Time period = 2 h

= 2 x 3600 = 7200 s

Time period of satellite

$T = \dfrac{2\pi}{R}\sqrt{\dfrac{(R+h)^3}{g}}$

R is the radius of planet

h is the height of satellite

$T^2 = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{g}}$

now calculation of acceleration due to gravity

$g = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{T^2}}$

$g = \dfrac{4\pi^2}{(4.15\times 10^6)^2}\ {\dfrac{(4.15\times 10^6+4.1\times 10^5)^3}{(7200)^2}}$

g = 4.15 m/s²

True weight of satellite

W = m g

W = 5850 x 4.15

W = 24277.5 N

W = 24.28 kN

True weight of the satellite is W = 24.28 kN

8 0

3 years ago