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SVEN [57.7K]
3 years ago
15

ASAP please 25 points if right

Physics
1 answer:
garik1379 [7]3 years ago
5 0

Answer:

1. The resistance of any physical object to any velocity

2. It continues in it's existing state of rest or uniform motion

3. Mass is a quantity that is solely dependent upon the inertia of an object.

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A cylinder of compressed gas has a pressure of 488.2 kPa. The next day the cylinder of gas has a
Luda [366]

Answer:

20 °C

Explanation:

Ideal gas law:

PV = nRT

Rearranging:

P / T = nR / V

Since n, R, and V are constant:

P₁ / T₁ = P₂ / T₂

488.2 kPa / T = 468 kPa / 281.15 K

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A pipe is open at both ends. The pipe has resonant frequencies of 528 Hz and 660HZ (among others).
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To develop this problem it is necessary to apply the oscillation frequency-related concepts specifically in string or pipe close at both ends or open at both ends.

By definition the oscillation frequency is defined as

f = n\frac{v}{2L}

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L = Length of the pipe

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Re-arrange to find L,

f = n\frac{v}{2L}\\L = \frac{nv}{2f}

The radius between the two frequencies would be 4 to 5,

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4:5

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Here f represents the fundamental frequency.

Now using the expression to calculate the Length we have

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Therefore the length of the pipe is 1.3m

For the second harmonic n=2, then

L = \frac{nv}{2f}\\L = \frac{(2)343m/s}{2(132)}\\L = 2.59m

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A place that limits a wave’s motion.
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Answer:

boundary

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