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3 years ago

I really appreciate u guys helping me

Physics

2 answers:

Gala2k [10]3 years ago

8 0

The answer is 1 because the earths axis is tilted and that is how it is suppose to be.

konstantin123 [22]3 years ago

4 0

The answer is number 4

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Which example identifies a change in motion that produces acceleration? choices are: 1. a speed skater moving at a constant spee

Oduvanchick [21]

Acceleration is a vector quantity that takes into account the changes in either the direction or the velocity or both. From the choices given, I go with choice number 2 where the body moves in a circular motion; thus, causing changes in its direction from time to time.

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3 years ago

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Prove that potential energy is equal to kinetic energy

Greeley [361]

Answer: when an object begins to fall its potential energy decreases and it’s kinetic energy increases, potential energy is equal to kinetic energy because a decrease in potential energy is exactly equal to the increase in kinetic energy.

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3 years ago

A ball is being thrown straight upward and rises to a maximum height of 12.0m above its launch point. At what height above it’s

AlexFokin [52]

Answer:

9.0 m

Explanation:

Let the initial velocity be 'u'.

Given:

Final velocity is half of initial velocity.

Maximum height reached by ball (H) = 12.0 m

Acceleration of the ball is due to gravity (g) = -9.8 m/s²(Downward)

Now, first, we will find initial velocity of the ball using equation of motion given as:

$v^2=u^2+2a(\Delta y)$

For maximum height, final velocity is 0 as the ball stops at the maximum height temporarily. So, $v=0\ m/s$

Also, $\Delta y=H=12\ m$

Now, plug in all the values and solve for 'u'.

$0^2=u^2+2(-9.8)(12)\\\\u^2=235.2\\\\u=\sqrt {235.2} =15.34\ m/s$

Now, consider the motion of the ball till the velocity reaches half of initial velocity.

So, final velocity (v) = $\frac{u}{2}=\frac{15.34}{2}=7.67\ m/s$

Now, again using the same equation and finding the new height now. Let the new height be 'h'.

So, equation of motion is given as:

$v^2=u^2+2ah\\7.67^2=15.34^2+2\times -9.8\times h\\58.83=235.2-19.6h\\\\19.6h=235.2-58.83\\\\19.6h=176.37\\\\h=\frac{176.37}{19.6}\approx9.0\ m$

Therefore, the height reached by the ball when velocity is decreased to one-half of the initial velocity is 9.0 m.

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3 years ago

I NEED HELP ASAP!!!!!

Ratling [72]

Answer:

D) momentum of cannon + momentum of projectile= 0

Explanation:

The law of conservation of momentum states that the total momentum of an isolated system is constant.

In this case, the system cannon+projectile can be considered as isolated, because no external forces act on it (in fact, the surface is frictionless, so there is no friction acting on the cannon). Therefore, the total momentum of the two objects (cannon+projectile) must be equal before and after the firing:

$p_i = p_f$

But the initial momentum is zero, because at the beginning both the cannon and the projectile are at rest:

$p_i = 0$

So the final momentum, which is sum of the momentum of the cannon and of the projectile, must also be zero:

$p_f = p_{cannon}+p_{projectile} =0$

6 0

4 years ago

Why could the beam of particles not have a neutral charge?

tino4ka555 [31]

Answer:

The positive and negative charges balance each other. Overall, the atom is uncharged (neutral). However, if something happens to make an atom lose or gain an electron then the atom will no longer be neutral. An atom that gains or loses an electron becomes an ion.

Explanation:

I think this is the answer : D

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3 years ago