Answer:
102.0 g/mol.
Explanation:
Aluminum oxide or Al2O3 is a chemical compound composed of 3 Oxygen and 2 aluminum atoms. Naturally, it is present in the form of mineral corundum in crystalline polymorphic forms. It holds significant importance in the preparation of Aluminium metal that is used as a refractory material.
To calculate the molar mass of Aluminum oxide, we will add the molar mass of 2 Al and 3 O atoms.
Since molar mass of Al is: 26.98 g
Molar mass of O is: 16.00 g
Molar mass of Al2O3
= (26.98)2 + (16.00) 3
= 53.96 + 48
= 101.96 g/mol
Since it is mentioned in question to round off the answer upto 4 significant figures, it will make the answer: 102.0 g/mol.
Hope it help!
Alkaline metal-group 1
Alkaline earth metals-group 2
halogens=group 7
noble gases-group 8 or o
transition metals are the actinides and the lactanides below the periodic table
It can be in either state.....
Answer:
Explanation:
Hello there!
In this case, by bearing to to mind the given conditions, it is firstly possible to determine the initial volume of the closed system via the ideal gas equation:
Which is V1 in the Charles' law:
And of course, T1 is 298.15 (25+273.15). Therefore, by solving for V2 as the final volume, we obtain:
Best regards!
Answer:
The answer to your question is: 234.7 cans
Explanation:
data
caffeine concentration = 3.55 mg/oz
10.0 g of caffeine is lethal
there are 12 oz of caffeine in a can
Then
3.55 mg ----------------- 1 oz
x mg -----------------12 oz (in a can)
x = 42.6 mg of caffeine in a can
Convert it to grams 42,6 mg = 0.0426 g of caffeine in a can
Finally
0.0426 g of caffeine ------------------ 1 can
10 g of caffeine ----------------- x
x = 10 x 1/0.0436 = 234.7 cans
