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2 years ago

1. Determine los gramos obtenidos de hidróxido de calcio [Ca(OH)2], al reaccionar 12 g de óxido de calcio (CaO) con agua.

Chemistry

1 answer:

Maru [420]2 years ago

5 0

Answer:

15,86 g Ca(OH)₂ ≅ 16 g

Explanation:

La ecuación química balanceada para la reacción entre el óxido de calcio (CaO) y el agua (H₂O) para formar hidróxido de calcio (Ca(OH)₂) es la siguiente:

CaO(s) + H₂O(l) → Ca(OH)₂(ac)

De acuerdo a esta ecuación, 1 mol de Ca(OH)₂ es producida a partir de 1 mol de CaO. Convertimos las moles a gramos utilizando la masa molecular (MM) de cada compuesto:

MM(CaO)= 40 g/mol Ca + 16 g/mol O = 56 g/mol

⇒ 1 mol CaO x 56 g/mol CaO = 56 g CaO

MM(Ca(OH)₂) = 40 g/mol Ca + (2 x 16 g/mol O) + (2 x 1 g/mol H) = 74 g/mol

⇒ 1 mol Ca(OH)₂ x 74 g/mol Ca(OH)₂ = 74 g Ca(OH)₂

Por lo tanto, la relación estequiometrica es:

1 mol Ca(OH)₂/1 mol CaO = 74 g Ca(OH)₂/56 g CaO

Multiplicando la relación estequiométrica por la masa real de CaO (12 g), obtenemos los gramos obtenidos de Ca(OH)₂:

12 g CaO x 74 g Ca(OH)₂/56 g CaO = 15,86 g Ca(OH)₂

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