I’m pretty sure it’s 150 joules
Ionization energy increases from left to right because the left wants to lose elctrons and the right wants to gain electron
As you go a group it is easier lose lose because the electrons are farther away from the nucleus and there is less attraction from the positive charges.
It should be 3p3. the p level can hold 6 electrons
Rubidium group 1, 1 valence electrons very reactive
Mg2,2 very reactive
Al 3, 3 reactive
<span>0.0687 m
The balanced equation is
BaCl2 + Na2SO4 ==> BaSO4 + 2 NaCl
Looking at the equation, it indicates that there's a 1 to 1 ratio of BaCl2 and Na2SO4 in the reaction. So the number of moles of each will be equal. Now calculate the number of moles of Na2SO4 we had. Start by looking up atomic weights.
Atomic weight sodium = 22.989769
Atomic weight sulfur = 32.065
Atomic weight oxygen = 15.999
Molar mass Na2SO4 = 2 * 22.989769 + 32.065 + 4 * 15.999 = 142.040538 g/mol
Moles Na2SO4 = 0.554 g / 142.040538 g/mol = 0.003900295 mol
Molarity is defined as moles per liter, so let's do the division.
0.003900295 mol / 0.0568 l = 0.068667165 mol/l = 0.068667165 m
Rounding to 3 significant figures gives 0.0687 m</span>
Answer: 14.625g
Explanation:
No of moles= mass given/molar mass
No of moles given= 0.375mol
Mass is the unknown (?)
Molar mass of K= 39
No of moles = mass given/molar mass
Substitute the values
0.375= mass/39
Cross multiply
Mass = 39×0.375
Mass= 14.625g
The mass is 14.625g
