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Andreyy89
3 years ago
5

Please answer it!! Would appreciate a lot!!

Chemistry
1 answer:
fomenos3 years ago
6 0

Answer:

1 acid

2 neutralization

3 H+ , OH-

4 metal

5 alkali

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formic acid buffer containing 0.50 M HCOOH and 0.50 M HCOONa has a pH of 3.77. What will the pH be after 0.010 mol of NaOH has b
HACTEHA [7]

Answer:

pH = 3.95

Explanation:

It is possible to calculate the pH of a buffer using H-H equation.

pH = pka + log₁₀ [HCOONa] / [HCOOH]

If concentration of [HCOONa] = [HCOOH] = 0.50M and pH = 3.77:

3.77 = pka + log₁₀ [0.50] / [0.50]

<em>3.77 = pka</em>

<em />

Knowing pKa, the NaOH reacts with HCOOH, thus:

HCOOH + NaOH → HCOONa + H₂O

That means the NaOH you add reacts with HCOOH producing more HCOONa.

Initial moles of 100.0mL = 0.1000L:

[HCOOH] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOOH

[HCOONa] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOONa

After the reaction, moles of each species is:

0.0500moles HCOOH - 0.010 moles NaOH (Moles added of NaOH) = 0.0400 moles HCOOH

0.0500moles HCOONa + 0.010 moles NaOH (Moles added of NaOH) = 0.0600 moles HCOONa

With these moles of the buffer, you can calculate pH:

pH = 3.77 + log₁₀ [0.0600] / [0.0400]

<h3>pH = 3.95</h3>

3 0
3 years ago
consider the balanced chemical equation below. when the chemical reaction was carried out calculated theoretical was yield for s
8_murik_8 [283]

Answer:

Explanation:

% yield = (actual yield / theoretical yield) X 100

For this question,

% yield = (150g/ 162 g) X 100 = 92.6%

7 0
3 years ago
When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, what hybrid orbitals are used by p
SSSSS [86.1K]

When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, hybrid orbitals that  are used by phosphorus in the pcl4 cations are one orbital of s and three orbital of p as it is sp³hydridised.

<h3>What is sp³ hybridization?</h3>

Hybridization is a process or system which specifies the shape and geometry of any element or molecule with bond angles too.

The pcl4 cation is sp³ hybridized because of the phosphorus behave as a central atom here and the 4 chloride molecules are attached with the p- orbitals to the phosphorus molecule.

Therefore, pcl4 cation  is sp³ hybridized.

Learn more about sp³ hybridization, here :

brainly.com/question/13062274

#SPJ4

5 0
2 years ago
What is the solubility of NH4Cl at 50°C?
NISA [10]

Answer : Option E) 50 grams.

Explanation : According to the solubility curves the compound NH_{4}Cl to dissolve at 50 °C in 100 mL of water will need 50 grams of the compound. It is clearly indicated in the graph which is marked with red that at 50°C approximately 50.4 grams of the compound NH_{4}Cl will be needed to dissolved in 100 mL of water to form a solution.


8 0
3 years ago
Read 2 more answers
What type of compound does the formula, CuCl2, represent?<br> a. ionic salt<br> b. covalent molecule
Rainbow [258]
The answer is:  [B]:  "ionic salt" .
___________________________________________________
Note:  There is no "sharing of electrons" among the elements in this compound; so this compound in NOT a "covalent molecule".

However, there is ionic bonding:  Cu²⁺ and  Cl⁻  ;  to form:  "CuCl₂" .
____________________________________________________ 
7 0
3 years ago
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