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lesantik [10]
3 years ago
15

Two flat 4.0 cm × 4.0 cm electrodes carrying equal but opposite charges are spaced 2.0 mm apart with their midpoints opposite ea

ch other. Between the electrodes but not near their edges, the electric field strength is 2.5 × 106 N/C. What is the magnitude of the charge on each electrode? (ε0 = 8.85 × 10-12 C2/N ∙ m2)
Physics
1 answer:
serious [3.7K]3 years ago
7 0

Answer:

1.77 x 10^-8 C

Explanation:

Let the surface charge density of each of the plate is σ.

A = 4 x 4 = 16 cm^2 = 16 x 10^-4 m^2

d = 2 mm

E = 2.5 x 10^6 N/C

ε0 = 8.85 × 10-12 C2/N ∙ m2

Electric filed between the plates (two oppositively charged)

E = σ / ε0

σ = ε0 x E

σ = 8.85 x 10^-12 x 2.5 x 10^6 = 22.125 x 10^-6 C/m^2

The surface charge density of each plate is ± σ / 2

So, the surface charge density on each = ± 22.125 x 10^-6 / 2

                                                                 = ± 11.0625 x 10^-6 C/m^2  

Charge on each plate = Surface charge density on each plate x area of each plate

Charge on each plate = ± 11.0625 x 10^-6  x 16 x 10^-4 = ± 1.77 x 10^-8 C

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erma4kov [3.2K]

Answer:

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6-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

Explanation:

#6 and 5 are the same

5 0
3 years ago
A large box has a mass of 500kg and the coefficient of static friction for the box and the floor is 0.45, and the coefficient of
Mumz [18]
A) The friction force while the box is stationary is (the coefficient of static friction)*(the normal force). In this case, the normal force is equal to the gravitational force, or the weight. To move the box, we need a minimum horizontal force that is equal to the friction force. The weight is (500 kg)*(9.81 m/s^2)= 4905 N. So, (0.45)*(4905 N) = 2207.25 N.

b) The acceleration will be the horizontal force - the kinetic friction force (since they act in opposite directions) divided by the mass. Kinetic friction force = (coefficient of kinetic friction)*(normal force or weight). 

F(net) = (2207.25 N)-(0.30)(4905 N) = 735.75 N

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4 0
3 years ago
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satela [25.4K]
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7 0
3 years ago
If the mass of a material is 48 grams and the volume of the material is 8 cm^3, what would the density of the material be?
iris [78.8K]
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So mass is 48 grams
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4 0
3 years ago
I mon runs a distance of 10km in 5 ms<br>he overage speed​
Harrizon [31]

<em>Note: Your question inputs seem a little odd. But, I am assuming that you really mean '10km in 5 ms'.</em>

<em></em>

Answer:

The Average speed = 15000 / 0.005 = 3000000 m/s

Explanation:

  • Average speed can be calculated by dividing the total distance covered by the total time.

Average speed = Total Distance / Total time

Given

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  • Total time = 5 ms = 0.005 seconds

Thus,  

Average speed = Total Distance / Total time

Average speed = 15000 / 0.005 = 3000000 m/s

7 0
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