Answer:
D). A sudden change in temperature increased the density of the atmosphere.
Explanation:
The claim that can be made and supported with evidence regarding the temporary decrease in light would be 'a sudden change in temperature will increase the density of the atmosphere.' <u>As the temperature increases, the molecules in the atmosphere begin to move fastly which causes a decrease in atmosphere density while it increases with the fall in temperature. As a result, the intensity of sunlight gets affected due to molecules being heavier and floating in the atmosphere</u>. Thus, <u>option D</u> is the correct answer.
Refraction is simply the bending of light when it moves from one material into another. If light is beamed at 90° to a surface, no bending happens. But if you shine the light at an angle it will bend one way or another.
Diffraction is a process in which a beam of light travels through a gap or around a barrier, and spreads out as a result.
<span> Dispersion is the property that the speed of light in a transparent material is different for different wavelengths. Thus the index of refraction is likewise different.</span>
Answer: initially the packet was ascending up with the balloon.
Taking upward as positive direction;
initial velocity, u = 4.9 m/s
final velocity = v m/s
initial height, h₁ = 245 m
final height, h₂ = 0
a = -9.8 m/s²
time taken = t seconds
s = ut + 0.5at²
⇒ (h₂-h₁) = ut + 0.5at²
⇒ 0-245 = 4.9t + 0.5×(-9.8)×t²
⇒ -245 = 4.9t - 4.9t²
⇒ 4.9t² -4.9t -245 =0
Solving it, we get t = 7.59s
v = u + at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/s
So velocity is 69.48 m/s downward
Explanation:
Answer:
The work done by Joel is greater than the work done by Jerry.
Explanation:
Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

Where:
- Work, measured in joules.
- Force exerted on the object, measured in newtons.
- Travelled distance by the object, measured in meters.
During the first 10 minutes, the net work exerted on the object is zero. That is:





In exchange, the net work in the next 5 minutes is the work done by Joel on the object:


Hence, the work done by Joel is greater than the work done by Jerry.
Usually in the deep sea and underwater caves where there is no light