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expeople1 [14]
3 years ago
13

Calculate the mass (in grams) of calcium carbonate present in a 50.00 mL sample of an aqueous calcium carbonate standard, assumi

ng the standard is known to have a hardness of 75.0 ppm (hardness due to CaCO3).
Chemistry
1 answer:
Natali5045456 [20]3 years ago
8 0
In one gram of standard, there are 75 × 10⁻⁶ grams of CaCO3
Thus, in 50 ml, there are 50 grams of standard (assuming density of standard equal to that of water) so grams of CaCO3 are:
50 × 75 × 10⁻⁶
= 3.75 × 10⁻³ grams
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Tiffany was investing how fast it took Hayden to react to different sounds. Identify the independent variable.
Hatshy [7]

Answer:

The different sounds

Explanation:

since it can not be changed

7 0
3 years ago
Choose the molecular compound among the substances listed below.
agasfer [191]

Answer: Among the listed substances XeCl_{4} is the molecular compound.

Explanation:

A chemical compound formed by the chemical combination of two or more non-metals is called a molecular compound or covalent compound.

For example, Xe and Cl are non-metals. The compound formed by them is XeCl_{4} which is a molecular compound.

A molecular compound is formed by sharing of atoms between the combining atoms.

Whereas NaF, MnCl_{2} and CaO are all ionic compounds as they are formed by chemical combination of a metal and a non-metal.

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4 0
2 years ago
I NEED HELP PLEASE ASAP! BRAINLIEST :)
Keith_Richards [23]

Answer:

6. d

7.c

8.a

9.b

Explanation:

For 6, the answers are not particularly close to 100, and they are not clustered much. For 7, the answers are all clustered very close to 100. For 8, the answers are clustered closely, but not close to 100. For 9, the answers are close to 100, but not clustered very tightly. Hope this helps!

6 0
3 years ago
43 moles feci3 are dissolved in 0.64l of solution what is the molarity of the solution
nasty-shy [4]
Molarity=moles/liter
molarity=43/0.64
molarity=67.19moles/litre
4 0
3 years ago
83ef0c8
kumpel [21]

Answer:

0.17325 moles per liter per second

Explanation:

For a first order reaction;

in[A] = in[A]o - kt

Where;

[A]= concentration at time t

[A]o = initial concentration

k= rate constant

t= time taken

ln0.5 =ln1 - 2k

2k = ln1 - ln0.5

k= ln1 - ln0.5/2

k= 0 -(0.693)/2

k= 0.693/2

k= 0.3465 s-1

Rate of reaction = k[A]

Rate = 0.3465 s-1 × 0.50 mol/L

Rate = 0.17325 moles per liter per second

5 0
2 years ago
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