Write a balanced equation for the combustion of liquid ethanol in air.
1 answer:
<u>Answer:</u> The balanced chemical equation for the combustion of liquid ethanol is written below.
<u>Explanation:</u>
Combustion reactions are defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water. Heat is released during these reactions.
A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
The balanced chemical equation for the combustion of liquid ethanol follows:
By Stoichiometry of the reaction:
1 mole of liquid ethanol reacts with 3 moles of oxygen gas to produce 2 moles of carbon dioxide gas and 3 moles of water vapor.
Hence, the balanced chemical equation for the combustion of liquid ethanol is written above.
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Answer:- 1.24 g
Solution:- The balanced equation for the formation of carbonic acid by the reaction of carbon dioxide with water is:
From balanced equation, there is 1:1 mol ratio between carbon dioxide and carbonic acid. So, moles of carbonic acid will be equal to the moles of carbon dioxide used.
Moles of carbon dioxide can be calculated using ideal gas law equation as it's volume, temperature and pressure are given.
we need to convert mL to L, degree C to kelvin and kilopascals to atm.
= 0.495 L
25 + 273 = 298 K
= 1 atm
Ideal gas law equation is:
PV = nRT
We want to find out the n, so let's rearrange this:
R is the universal gas constant and it's value is .
Let's pug in the values in the equation and solve it for n.
n = 0.02 mol
To convert the moles to grams we multiply the moles by the molar mass of carbonic acid.
Molar mass of carbonic acid = 2(1.008)+12.01+3(16.00)
= 2.016+12.01+48.00
= 62.03 gram per mol (rounded to two decimal places)
Let's multiply the moles by molar mass:
= 1.24 g
So, the theoretical yield of carbonic acid is 1.24 g.