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Nikitich [7]
3 years ago
13

Write a balanced equation for the combustion of liquid ethanol in air.

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
7 0

<u>Answer:</u> The balanced chemical equation for the combustion of liquid ethanol is written below.

<u>Explanation:</u>

Combustion reactions are defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water. Heat is released during these reactions.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the combustion of liquid ethanol follows:

C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(g)

By Stoichiometry of the reaction:

1 mole of liquid ethanol reacts with 3 moles of oxygen gas to produce 2 moles of carbon dioxide gas and 3 moles of water vapor.

Hence, the balanced chemical equation for the combustion of liquid ethanol is written above.

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27.6mL of LiOH 0.250M

Explanation:

The reaction of lithium hydroxide (LiOH) with chlorous acid (HClO₂) is:

LiOH + HClO₂ → LiClO₂ + H₂O

<em>That means, 1 mole of hydroxide reacts per mole of acid</em>

Moles of  20.0 mL = 0.0200L of 0.345M chlorous acid are:

0.0200L ₓ (0.345mol / L) = <em>6.90x10⁻³ moles of HClO₂</em>

To neutralize this acid, you need to add the same number of moles of LiOH, that is 6.90x10⁻³ moles. As the LiOH contains 0.250 moles / L:

6.90x10⁻³ moles ₓ (1L / 0.250mol) = 0.0276L of LiOH =

<h3>27.6mL of LiOH 0.250M</h3>
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