Answer: The pressures of
,
, and
in an equilibrium mixture are 0.4 atm , 0.2 atm and 6.6 atm respectively.
Explanation:
Initial pressure of
= 7.0 atm
Initial pressure of
= 3.5 atm
The given balanced equilibrium reaction is,
Initial pressure 7.0 atm 3.5 atm 0 atm
At eqm. conc. (7-2x)atm (3.5-x)atm (2x) Matm
The expression for equilibrium constant for this reaction will be,
we are given : 
Now put all the given values in this expression, we get :
Pressure of
at equilibrium = (7-2x) = 
pressure of
at equilibrium = (3.5-x) = 
pressure of
at equilibrium = (2x) = 