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2 years ago

5

Which theorist said we all have and are motivated by five basic human needs? He is from Cleveland, Ohio. He talks about how we c

hoose everything.

1 answer:

bixtya [17]2 years ago

6 0

Answer:

abraham maslow

Explanation:

I'm surprised i remembered that. I hope that's correct, good luck on whatever you're doing :)

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A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =

Ratling [72]

Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

$v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2$

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

$v = \omega R\\a = \alpha R$

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

$v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft$

One revolution is equal to the circumference of the drum. So, total number of revolutions is

$x / (2\pi R) = 6/(\pi R)$

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

$a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2$

b) $a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2$

5 0

3 years ago

the light from andromeda galaxy takes about 2.6 million years to reach earth. which of these statements is correct about the and

-Dominant- [34]

A. it is <span>located at a distance of 2.6 million light years from earth</span>

7 0

3 years ago

A 100 kg box sits on an incline held at rest by a very thin rope attached to another mass hanging as shown. The force of frictio

MAVERICK [17]

If friction is acting along the plane upwards

then in this case we will have

For equilibrium of 100 kg box on inclined plane we have

$mgsin\theta = F_f + T$

also for other side of hanging mass we have

$T = Mg = 50(9.8) = 490 N$

now we have

$100(9.8)sin\theta = 100 + 490$

$980sin\theta = 590$

$sin\theta = 0.602$

$\theta = 37 degree$

In other case we can assume that friction will act along the plane downwards

so now in that case we will have

$mgsin\theta + F_f = T$

also we have

$T = Mg = 50(9.8) N$

now we have

$100(9.8)sin\theta + 100 = 50(9.8)$

$980sin\theta + 100 = 490$

$980 sin\theta = 490 - 100$

$sin\theta = 0.397$

$\theta = 23.45 degree$

<em>So the range of angle will be 23.45 degree to 37 degree</em>

6 0

3 years ago

A box-shaped wood stove has dimensions of 0.75 mx 1.2 m x 0.4 m, an

Tresset [83]

Answer:

8.4 kW

Explanation:

Using the Stefan-Boltzmann law,

P = εAσT4

Where:

P: Radiation Energy

ε: Emissivity of the Surface. Check emissivity table below of common materials.

A: Surface Area, in m^2.

σ: Stefan-Boltzmann Constant, σ=5.67 × 10-8 W/m2•K4

T: Temperature

Plugging in values,

P = 0.85 x 3.328 x 5.67 x 10^(-8) x 205

P = 8383 W or 8.4 kW

3 0

3 years ago

Andrews [41]

Given :

A 13.3 kg box sliding across the ground decelerates at 2.42 m/s².

To Find :

The coefficient of kinetic friction.

Solution :

Frictional force applied to the box is :

$f = ma$ ....1)

Also, force of friction is given by :

$f = \mu mg$ ....2)

Equating equation 1) and 2), we get :

$\mu mg = ma\\\\\mu = \dfrac{a}{g}\\\\\mu = \dfrac{2.42}{9.8}\\\\\mu = 0.247$

Therefore, the coefficient of kinetic friction is 0.247 .

8 0

3 years ago