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Likurg_2 [28]
3 years ago
13

Calculate the amount of energy released in the formation of one mole of BaSe bonds (not lattice energy). The radius of the bariu

m ion is 1.35 Å, and the radius of the selenide ion is 1.98 Å. Note that 1Å=10−10m.
Chemistry
1 answer:
zysi [14]3 years ago
3 0
The correct answer for the question that is being presented above is this one: "2.02x10^3 kJ/mol." Calculate the amount of energy released in the formation of one mole of BaSe bonds (not lattice energy). The radius of the barium ion is 1.35 Å, and the <span>radius of the selenide ion is 1.98 Å. Note that 1Å=10−10m.</span>
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A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added, and the
BARSIC [14]

Answer:

Rb+

Explanation:

Since they are telling us that the equivalence point was reached after 17.0 mL of   2.5 M HCl were added , we can calculate the number of moles of HCl which neutralized our unknown hydroxide.

Now all the choices for the metal cation are monovalent, therefore the general formula for our unknown is XOH and  we know the reaction is 1 equivalent acid to 1 equivalent base. Thus we have the number of moles, n,  of XOH and from the relation n = M/MW we can calculate the molecular weight of XOH.

Thus our calculations are:

V = 17.0 mL x 1 L / 1000 mL = 0.017 L

2.5 M HCl x 0.017 L = 2.5 mol/ L x 0.017 L = 0.0425 mol

0.0425 mol = 4.36 g/ MW XOH

MW of XOH = (atomic weight of X + 16 + 1)

so solving the above equation we get:

0.0425 = 4.36 / (X + 17 )

0.7225 +0.0425X = 4.36

0.0425X = 4.36 -0.7225 = 3.6375

X = 3.6375/0.0425 = 85.59

The unknown alkali is Rb which has an atomic weight of 85.47 g/mol

6 0
3 years ago
If you have 40 grams of potassium nitrate in 100 grams of water at 20 C:
anygoal [31]

Answer:

Explanation:The final homogenous solution, after cooling it to 40°C, will contain 47 g of potassium sulfate disolved in 150 g of water, so you can calculate the amount disolved per 100 g of water in this way:

[47 g of solute / 150 g of water] * 100 g of g of water = 31.33 grams of solute in 100 g of water.

So, when you compare with the solutiblity, 15 g of solute / 100 g of water, you realize that the solution has more solute dissolved with means that it is supersaturated.

To make a saturated solution, 15 grams of potassium sulfate would dissolve in 100 g of water.

Read more on Brainly.com - brainly.com/question/5143785#readmore

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3 years ago
In his version of the periodic table, mendeleev based his arrangement of the elements on an element's _________. atomic number c
sammy [17]
ʜᴇʟʟᴏ ᴛʜᴇʀᴇ!

In his version of the periodic table, Mendeleev based his arrangement of the elements on an element's atomic mass.

нσρє тнιѕ нєℓρѕ уσυ!
gσσ∂ ℓυ¢к :)
нανє α gяєαт ∂αу  

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3 years ago
Which description of salt is a physical property?
Genrish500 [490]

Answer:

salt is dull and brittle and conducts electricity when it has been dissolved into water, which it does quite easily.

Explanation:

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