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3 years ago

Describe what the greenhouse effect is and how it is caused on a molecular level.

1 answer:

6 0

The greenhouse effect is the process by the temperature of surface of earth increases because of earth's atmosphere.

Mechanism:

Sun emits a broad band of visible light spanning from red to blue colour. In addition to this, it emits UV and IR radiation. Infrared radiations have wavelength longer than IR, while UV ray have wavelength shorter than visible light. Each of these radiations are received on the earth's surface. On receiving radiation, part of it is absorbed by earth and remaining is reflected back. Generally, light of longer wavelength (IR) is reflected to larger extend as compared to shorter wavelength. Due to this, air present in atmosphere gets heated up. It must be noted that, molecule like CO2, which is present in air absorbs light from both direct and reflected fraction of light. This phenomenon is referred as green house effect. Molecule which absorb long wavelength light (IR) are present in atmosphere due to human activities. Hence, green house effect is often considered to arise because of human activities of altering the composition of air.

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Number of molecules in 4HCl

katrin2010 [14]

Answer:

its not cear to answer this question

6 0

2 years ago

33.56 g of fructose (C6H,206) and 18.88 g of water are mixed to obtain a 40.00 ml solution a. What is this solution's density? b

Darina [25.2K]

Explanation:

Mass of fructose = 33.56 g

Mass of water = 18.88 g

Total mass of the solution = Mass of fructose + Mass of water = M

M = 33.56 g + 18.88 g =52.44 g

Volume of the solution = V = 40.00 mL

Density = $\frac{Mass}{Volume}$

a) Density of the solution:

$\frac{M}{V}=\frac{52.44 g}{40.00 mL}=1.311 g/mL$

b) Molar mass of fructose = 180.16 g/mol

Moles of fructose = $n_1=\frac{ 33.56 g}{180.16 g/mol}=0.1863 mol$

Molar mass of water = 18.02 g/mol

Moles of water= $n_2=\frac{ 18.88 g}{18.02 g/mol}=1.0477 mol$

Mole fraction of fructose in this solution: $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1863 mol}{0.1863 mol+1.0477 mol}$

$\chi_1=0.1510$

Mole fraction of water = $\chi_2=1-\chi_1=0.8490$

c) Average molar mass of of the solution:

= $\chi_1\times 180.16 g/mol+\chi_2\times 18.02 g/mol$

$=0.1510\times 180.16 g/mol+0.8490\times 18.02 g/mol=42.50 g/mol$

d) Mass of 1 mole of solution = 42.50 g/mol

Density of the solution = 1.311 g/mL

d) Specific molar volume of the solution:

$\frac{\text{Average molar mass}}{\text{Density of the mass}}$

$=\frac{42.50 g/mol}{1.311 g/mL}=32.42 mL/mol$

5 0

3 years ago

Which of the following is a way in which water resources are consumed? a. drinking b. industry c. business d. all of the above P

kirill [66]

all of the above is the correct answer

3 0

3 years ago

Identify the missing coefficient in the balanced equation and classify the type of reaction.

Lostsunrise [7]

Answer:

Option 6 ) Neutralization

Explanation:

For this case, the missing coefficient would be a "6" before the H₂O, within final products (right side of the equiation), hence, the final reaction should be:

2H₃PO₄ + 3Ba(OH)₂ ------> Ba₃(PO₄)₂ + 6H₂O

You should have in mind that the amount of atoms at each side of the chemical equation should be the same, so as to comply with the principle of mass conservation. If you add "6" on the left side of the H₂O, the equation will be balanced (for each side, lef and right, you will have: 12H, 2P, 14O and 3Ba)

Lastly, this is a chemical neutralization reaction, where an acid (H₃PO₄) is reacting with a base (Ba(OH)₂) in order to finally obtain a neutral salt (Ba₃(PO₄)₂) and water (H₂O)

5 0

3 years ago

Read 2 more answers

Calculate the amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C.

qwelly [4]

Answer:

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

c= 4.184 $\frac{J}{g*C}$
m= 32 g
ΔT= Tfinal - Tinitial= 22°C - 8°C= 14°C

Replacing:

Q= 32 g* 4.184 $\frac{J}{g*C}$ *14 °C

Solving:

Q= 1,874.432 J

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

7 0

2 years ago