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iogann1982 [59]
3 years ago
10

WILL GIVE BRAINLIST

Chemistry
1 answer:
8_murik_8 [283]3 years ago
4 0
I would choose C bc if u look at it closely u can notice it goes up steadily and then BANG it decreases a lot
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After the reaction between sodium borohydride and the ketone is complete, the reaction mixture is treated with water and H2SO4 t
In-s [12.5K]

Answer:

The hydrogen can be gotten from the added Acid or water during "workup".

Explanation:

Basically we can say that the reaction describe in this question is a Reduction reaction because of the chemical compound called sodium borohydride. In the reaction described above we can see that there is a Reduction of ketone to alcohol by the compound; sodium borohydride.

For the reduction Reaction to occur the C-O bond must break so as to enable the formation of O-H bond and C-H bond.

So, "the reaction mixture is treated with water and H2SO4 to produce the desired alcohol", thus, the oxygen will definitely pick up the hydrogen from H2SO4 or H2O.

7 0
3 years ago
1. Pewien tlenek azotu o masie cząsteczkowej 108 u zawiera 74,07% tlenu. Wykonaj stosowne obliczenia i napisz wzór sumaryczny te
love history [14]

Answer:

1. Stąd empiryczny wzór substancji to N₂O₅

2. W związku z tym ilość w gramach chlorku sodu NaCl is 114,4 g.

Explanation:

1. Mamy tutaj;

Masa molowa tlenku azotu = 108u

Masa azotu = 14,0067u

Masa tlenu = 15,999 u

74,07% masy tlenku azotu to tlen

Dlatego masa obecnego tlenu = 108 × 74,07 / 100 = 79,9956 u

Masa obecnego azotu = 108 - 79,9956 = 28,0044u

Liczba moli tlenu = 79,9956 / 15,999 = 5,00003 ≈ 5

Liczba moli azotu = 28,0044 / 14,0067 = 1,99935 ≈ 2

Stąd empiryczny wzór substancji to N₂O₅.

2. Kiedy sód reaguje z chlorem, mamy;

2Na (s) + Cl₂ (g) → 2NaCl (s)

Dlatego 2 mole sodu Na reaguje z 1 molem chloru gazowego Cl₂, z wytworzeniem 2 moli chlorku sodu NaCl

W związku z tym 1 mol sodu Na reaguje z 1/2 molem chloru gazowego Cl₂ z wytworzeniem 1 mola chlorku sodu NaCl

Masa Na obecnego w reakcji = 45 g

Masa molowa sodu = 22,989769u

Liczbę moli sodu w 45 g sodu podano w następujący sposób;

Liczba \, \, moli \, \, Na= \frac{Mass \, of \, Na}{Molowy \, masa \, z \, Na} = \frac{45}{22.989769} = 1.96 \, mole

Z czego 1,96 moli sodu Na reaguje z 1/2 × 1,96 mola chloru gazowego Cl₂ z wytworzeniem 1,96 mola chlorku sodu NaCl

Masa molowa NaCl = 58,44 g / mol

Dlatego masa NaCl = liczba moli NaCl × masa molowa NaCl

Masa NaCl = 1,96 × 58,44 = 114,39001 g ≈ 114,4 g

W związku z tym ilość w gramach chlorku sodu NaCl = 114,4 g.

4 0
2 years ago
Elements bond when they share or transfer their outer shell electrons which are called valence electrons
rusak2 [61]

Answer:

True

Explanation:

3 0
3 years ago
Why does the Moon orbit Earth instead of the Sun?
Vera_Pavlovna [14]
Gravity depends on distance and the moon is closer to earth
4 0
2 years ago
Fill in the coefficients that will balance the following reaction: a0Ca + a1CO2 + a2O2 → a3CaCO3
VashaNatasha [74]
The chemical equation without coefficients is:


Ca + CO2 + O2 --------> Ca CO3


You can balance that equation by trial an error.


This is the chemical equation balanced:


2Ca + 2CO2 + O2 --------> 2Ca CO3


Count the atoms on each side to check the balance


Atom    Left side         right side

Ca         2                     2 

C           2                     2

O          2*2 + 2 = 6       2*3 = 6


Then those are the coefficients:

a0 = 2

a1 = 2

a2 = 1

a3 = 2
6 0
3 years ago
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