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AlladinOne [14]
3 years ago
8

Riley is doing an experiment working with friction. He wants to find two ways to modify an object that could increase or decreas

e the same type of friction.
Which methods could he use to perform his experiment?
Chemistry
2 answers:
Shtirlitz [24]3 years ago
5 0
Riley can either change the surface area of the object or can change the slipperiness of the material.
valentina_108 [34]3 years ago
5 0

Answer:the answer is B increasing the surface area and areodynamic design. Just took the test .

Explanation:

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Where do the letters go help me plz​
Montano1993 [528]

Answer:

For d I'm pretty sure its Organ System, I apologies if I am wrong

5 0
2 years ago
Read 2 more answers
A scientist wants to make a solution of tribasic sodium phosphate, na3po4, for a laboratory experiment. How many grams of na3po4
natima [27]

Answer :

The correct answer is for mass of Na₃PO₄ 39.7 g.

Given  : 1) Molarity of Na⁺ ions = 1.00 M or 1.00 \frac{mol}{L}

2) Volume of solution = 725 mL

Converting volume of solution from mL to L :

Conversion factor : 1 L = 1000 mL  

Volume of solution = 725 mL * \frac{1L }{1000 mL}

Volume of solution = 0.725 L


Following steps can be  done to find mass of  :

<u>Step 1 : Write the dissociation reaction of Na₃PO₄ .</u>

Na_3PO_4    3 Na^+  +  PO_4^3^-

<u>Step 2:  Find moles of Na⁺ ions : </u>

Mole of Na⁺ ions can be calculated using molarity formula  which is :Molarity (\frac{mol}{L} ) = \frac{mole of Na^+ }{volume of solution }

Plugging value of Molarity and volume

1.00 \frac{mol}{L} = \frac{Mole of Na^+ ions}{0.725 L}

Multiplying both side by 0.725 L

1.00 \frac{mol}{L}* 0.725 L = \frac{mole of Na^+ ions}{0.725 L} * 0.725 L

<em>Mole of Na⁺ ions = 0.725 mol</em>

<u>Step 3: Find mole ratio of Na₃PO₄ : Na⁺ :</u>

Mole ratio  is found from coefficients from balanced reaction as:

Mole of Na₃PO₄ in balanced reaction = 1

Mole of Na⁺ ion =  3

<em>Hence mole ratio of Na₃PO₄: Na⁺ = 1 : 3 </em>

<u>Step 4 : To find mole of Na₃PO₄ </u>

Mole of Na₃PO₄ can be calculated using mole of Na⁺ ion and Mole ratio as :

Mole of Na_3PO_4= Mole of Na^+  * Mole ratio

Mole of Na_3PO_4 = 0.725 mol  *  \frac{1 mole of Na_3PO_4}{3 mole of Na^+ }

<em>Mole of Na₃PO₄ =  0.242 mol </em>

<u>Step 5 : To find mass of Na₃PO₄</u>

Mole of Na₃PO₄ can be converted to mass of Na₃PO₄ using  molar mass of Na₃PO₄ as :

Mass (g) = mole (mol) * molar mass \frac{g}{mol}

Mass of Na_3PO_4 =  0.242 mol * 163.94 \frac{g}{mol}

Mass of Na₃PO₄ = 39.619 g

<u>Step 6 : To round off mass of Na₃PO₄ to correct sig fig .</u>

The sig fig in 750 mL and 1.00 M is 3 . So mass of Na₃PO₄ can rounded to 3 sig fig as :

Mass of Na₃PO₄ = 39.7 g


8 0
3 years ago
PLEASE HELP <br> describe the process of paper chromatography????????????
irinina [24]

Answer:Chromatography technique that uses paper sheets or strips as the adsorbent being the stationary phase through which a solution is made to pass is called paper chromatography. It is an inexpensive method of separating dissolved chemical substances by their different migration rates across the sheets of paper.

You're welcome :)

5 0
3 years ago
Recording a person’s fingerprints using ink or digital imaging is called a(n)____.
NNADVOKAT [17]
It is called a dactyloscopy
5 0
3 years ago
How many milliliters of 0.1 m hcl is required to react with 0.15g sodium carbonate (na2co3?
docker41 [41]
1) Write the balanced chemical equation

     2HCl + Na2 CO3 ----------> 2NaCl + H2CO3

2) Write the molar ratios:

    2 mol HCl : 1 mol Na2CO3 : 2 mol NaCl : 1 mol H2CO3

3) Convert 0.15g of sodium carbonate to number of moles

3a) Calculate the molar mass of Na2CO3

Na: 2 * 23 g/mol = 46 g/mol

C: 12 g/mol =

O: 3 * 16 g/mol = 48 g/mol

molar mass = 46g/mol + 12g/mol + 48g/mol = 106 g/mol

3b.- Calculate the number of moles of Na2CO3

# moles = grams / molar mass = 0.15 g / 106 g/mol = 0.0014 mol Na2CO3

4) Calculate the number of moles of HCl from the molar proportion:

[0.0014 mol Na2CO3] * [2 mol HCl / 1 mol Na2CO3] = 0.0028 mol HCl

5) Calculate the volume of HCl from the definition of Molarity

Molarity, M = # moles / volume in liters

=> Volume in liters = # moles / M = 0.0028 mol / 0.1 M = 0.028 liters

0.028 liters * 1000 ml / liter = 28 ml.

Answer: 28 mililiters of 0.1 M HCl.
7 0
3 years ago
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