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AlladinOne [14]
3 years ago
8

Riley is doing an experiment working with friction. He wants to find two ways to modify an object that could increase or decreas

e the same type of friction.
Which methods could he use to perform his experiment?
Chemistry
2 answers:
Shtirlitz [24]3 years ago
5 0
Riley can either change the surface area of the object or can change the slipperiness of the material.
valentina_108 [34]3 years ago
5 0

Answer:the answer is B increasing the surface area and areodynamic design. Just took the test .

Explanation:

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Write the ionic charges (such as Ca2+) and chemical formulas and fill-in the table below.
Vikentia [17]

1) Lithium and fluorine:

Ionic charges: lithium cation Li⁺ and fluorine anion F⁻.

Chemical formula LiF.

In ionic salt lithium fluoride (LiF), fluorine has electronegativity approximately χ = 4 and lithium χ = 1 (Δχ = 4 - 1; Δχ = 3).

Fluorine attracts electron and it has negative charge and lithium has positive charge.

2) Beryllium and oxygen:

Ionic charges cation Be²⁺ and anion O²⁻.

Chemical formula is BeO.

Beryllium is metal from group 2 and oxygen is nonmetal from group 16.

Electron configuration of beryllium: ₄Be: 1s² 2s², it has two valence electrons in 2s orbital.

Beryllium lose two electrons and to gain electron configuration as noble gas helium (He).

Electron configuration of oxygen atom: ₈O 1s² 2s² 2p⁴.

Oxygen gain two valence electron to form anion with stable electron configuration as noble gas neon (atomic number 10).

3) Magnesium and fluorine:  

Ionic charges cation Mg²⁺ and anion F⁻.

Chemical formula is MgF₂.

Magnesium fluoride (MgF₂) is salt, ionic compound.  

Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).  

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.  

Fluorine (F) is nonmetal with greatest electronegativity, which means it easily gain electrons.  

Fluorine has atomic number 9, which means it has 9 protons and 9 electrons. It gain one electron to form fluorine anion (F⁻) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.  

4) Aluminum and chlorine:  

Ionic charges cation Al³⁺ and anion Cl⁻.

Chemical formula is AlCl₃.

The right name for AlCl₃ is aluminium chloride.

Aluminium chloride is a salt with ionic bonds.

Aluminium (metal from group 13) has oxidation number +3 and chlorine (nonmetal from group 17) has oxidation number -1, chemical compound has neutral charge (+3 + 3 · (-1) = 0).

5) Beryllium and nitrogen:  

Ionic charges cation Be²⁺ and anion N³⁻.

Chemical formula is Be₃N₂.

Atomic number of nitrogen is 7, it has 7 protons and 7 electrons.

Electron configuration of nitrogen atom: ₇N 1s² 2s² 2p³.

Nitrogen gain three electrons to form anion with stable electron configuration as noble gas neon (atomic number 10).

4 0
3 years ago
During the combustion of NH3, there is an increase in the amount of oxygen present, from 5 to 20 moles while the amount of NH3 r
borishaifa [10]

Explanation:

The ratio of NH3 to NO produced will remain constant since NH3 is the limiting reactant.

Here in this reaction for every 4 moles of ammonia and 5 moles of oxygen gas , 4 moles of NO and 6 moles of water are formed.

So when the amount of oxygen gas is increased to 20 moles without changing the amount of ammonia , the amount of NO formed does not increase as ammonia becomes the limiting reactant.

6 0
3 years ago
How many climates does Australia have
zalisa [80]
Australia has 4 climates

8 0
3 years ago
Read 2 more answers
How fast is an electron travelling If it has a wavelength of 8.20 km?
Lemur [1.5K]

The electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

<h3>How to calculate velocity of an electron?</h3>

The velocity at which an electron travels can be calculated using the following formula:

λ = h/mv

Where;

  • H = Planck's constant
  • m = mass of electron
  • v = velocity of electron
  • λ = wavelength

  • Planck's constant (h) = 6.626 × 10−³⁴ J⋅s.
  • mass of electron (m) = 9.109 × 10−³¹ kg
  • wavelength = 8200m

8200 = 6.626×10−³⁴ / 9.109 × 10−³¹V

8200 = 7.3 × 10-⁴V

V = 8200 ÷ 7.3 × 10-⁴

V = 1.123 × 10⁷m/s

Therefore, the electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

Learn more about velocity at: brainly.com/question/13171879

#SPJ1

5 0
2 years ago
Consider this reaction:
Gre4nikov [31]

Answer:

[Cl2O5] = 1.60 M

Explanation:

  • 2Cl2O5(g) → 2Cl2(g) + 5O2(g)

at T ⇒ r = (17.4/M.s)*[Cl2O5]²

1) [Cl2O5] = 1.46 M

⇒ t = 0.400 s ⇒ [Cl2O5] = ?

rate law gnral:

  • - ra = K(Ca)∧α = - δCa/δt

∴ K = 17.4 /M.s

∴ α = 2

⇒ - ∫δCa/Ca² = K∫δt

⇒ [ 1/Ca - 1/Cao ] = K*t

⇒ 1/Ca = K*t + 1/Cao

⇒ Ca = 1/K*t + Cao = [Cl2O5]

∴ Cao = 1.46 M

∴ t = 0.400 s

⇒ [Cl2O5] = 1/[(17.4/M.s)*(0.400s)] + 1.46 M

⇒ [Cl2O5] = 0.1436 M + 1.46 M

⇒ [Cl2O5] = 1.604 M

3 0
4 years ago
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