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IRISSAK [1]
4 years ago
7

What is diffusion and how does it work

Chemistry
2 answers:
Elina [12.6K]4 years ago
8 0
Diffusion is the intermingling of substances by the natural movement of their particles.
It is when a substance enters and leaves cells. That is how it works.
shepuryov [24]4 years ago
6 0
Diffusion is the net movement of particles from a hight concentration to a low one
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As the deapth of the ocean increases the population of ocean creatures..
Trava [24]

Answer:

( A ) Increases

Explanation:

More room, basically means more creatures. Like in a bedroom, you can only fit amount of people if its small the ocean is like that with depth.

Hopefully this makes sense???

3 0
3 years ago
Read 2 more answers
Plz need help right away !
jeyben [28]

Explanation:

1 mole = 6.02 x 10^23 atoms (Avogadro’s number)

Step 1) Determine how many grams of a substance are in the problem

Step 2) Find the amount of grams in 1 mole of the substance

3) Multiply step one by step two

4 0
3 years ago
When 20 ml of 0.1 M HCl is mixed with 20
Bas_tet [7]

Answer:

it is b i took the test

Explanation:

4 0
2 years ago
What is the mass of a piece of iron that releases 179.85 joules of heat as it cools from 51.29 degrees Celsius to 31.42 degrees
Sedaia [141]

Answer:

20.11 g.

Explanation:

What is given?

c (specific heat of iron) = 0.450 J/g °C.

Q (heat energy) = 179.85 J.

ΔT (change of temperature) = |31.42 °C - 51.29 °C| = 19.87 °C.

What do we need? Mass of iron (m)

Step-by-step solution:

Let's see the formula of specific heat:

c=\frac{Q}{m\cdot\Delta T}

Where c is specific heat, Q is heat energy, m is mass and ΔT is the change of temperature.

We just have to solve for 'm' to find the mass of iron and replace the given data that we have, like this:

m=\frac{Q}{c\cdot\Delta T}=\frac{179.85\text{ J}}{0.450\text{ }\frac{J}{g\cdot\degree C}\cdot19.87\degree C}=20.11\text{ g.}

The mass of the iron would be 20.11 g.

5 0
2 years ago
A bubble of helium gas has a volume of 0.65 L near the bottom of a large
Flura [38]

Answer:

0.73L

Explanation:

The following data were obtained from the question :

V1 = 0.65 L

P1 = 3.4 atm

T1 = 19°C = 19 + 273 = 292K

V2 =?

P2 = 3.2 atm

T2 = 36°C = 36 + 273 = 309K

The bubble's volume near the top can be obtain as follows:

P1V1 /T1 = P2V2 /T2

3.4 x 0.65/292 = 3.2 x V2 /309

Cross multiply to express in linear form as shown below:

292 x 3.2 x V2 = 3.4 x 0.65 x 309

Divide both side by 292 x 3.2

V2 = (3.4 x 0.65 x 309) /(292 x 3.2)

V2 = 0.73L

Therefore, the bubble's volume near the top is 0.73L

8 0
3 years ago
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