Longitudinal. (just remember that Transverse waves are perpendicular. T is like an inverted perpendicular sign)
Molecular is existent due to being made out of molecules, and thus taking up space until a container cannot hold more.
Ionic substances are a little different they are made out of energy, thus taking up only the amount of energy a certain area can handle. Ionic substances also will show motion of energy as well.
<h3><u>Answer;</u></h3>
As, & Sr --------[Kr]
Be ------------------- [He]
O, & Mg ----------[Ne]
S, & Ca -------------[Ar]
<h3><u>Explanation</u></h3>
- <u>The Be+ ion has 2 electrons, just like He. The ions Mg2+ and O2− each has 10 electrons like Ne. </u>
- <u>The S2− and Ca2+ each has 18 electrons like Ar. The ions As3− and Sr+ each have 36 electrons like Kr.</u>
- <u>Atoms of elements lose or gain electrons to attain a stable configuration which is equivalent to the configuration of noble gases.</u>
- When atoms lose or gain electrons they form ions, which are either positively charged or negatively charged. When atoms lose electrons they form positively charged ions while if they gain electrons the form negatively charged ions
Answer:
The correct answer is 1.778 milligrams per liter.
Explanation:
Based on the given information, the concentration of chlorine gas given is 27 pounds or 27*453.59 = 12327.93 grams.
The quantity of water given is 750000 gallons or 750000 * 3.754 = 2815500 L
The concentration of chlorine used up by the microorganism is 2.6 mg/L or 0.0026 gm/L.
Thus, for 2815500 L of water, the amount of chlorine used is,
= 2815500 * 0.0026
= 7320.3 grams
The left quantity of chlorine is 12327.93 - 7320.3 = 5007.63 grams
The concentration of residual chlorine is,
= 5007.63 g/2815500 = 0.00177859 or 1.778 mg/L.
Answer:
[NaCH₃COO] = 2.26M
Explanation:
17% by mass is a sort of concentration. Gives the information about grams of solute in 100 g of solution. (In this case, 17 g of NaCH₃COO)
Let's determine the volume of solution, by density
Mass of solution / Volume of solution = Solution density
100 g / Volume of solution = 1.09 g/mL
100 g / 1.09 g/mL = 91.7 mL
17 grams of solute is contained in 91.7 mL
Molarity (M) = Mol of solute /L of solution
91.7 mL / 1000 = 0.0917L
17 g / 82 g/m = 0.207 moles
Molariy = 0.207 moles / 0.0917L → 2.26M