Answer:
= 15.51 mL
Explanation:
Here's is the reaction:
2HgO(s) ⇒ 2 Hg(s)+O₂(g)
In this reaction 2mol HgO = 1mol O₂
The molecular weight of HgO = 216.59g
so, 3.0g HgO = 3.0g x 1.00molHgO/216.59gHgO
= 0.0138511 molHgO
The amount of Oxygen follows:
0.0138511 molHgOx1/2= 0.00692555 mol O₂
Now, volume of 1 any gas = 22400mL
so, 0.00692555 mol O₂ x22400mLO₂/1mol O₂
= 15.513232mL O₂
Answer:
C₁₆H₃₂O₂ (s) + 22O₂(g) → 16CO₂(g) + 16H₂O(g)
Explanation:
In order to determine a combustion reaction we should know that:
Reactants are: X compound and O₂
Products are: CO₂ and H₂O
In this case, the X compound is the solid palmitic acid: C₁₆H₃₂O₂
The balanced equation will be:
C₁₆H₃₂O₂ (s) + 22O₂(g) → 16CO₂(g) + 16H₂O(g)
sodium hydroxide (NAOH) a.k.a causic soda commonly used in labs.
- MOLAR MASS of naoh is 39.997 g/mol.
- It is dry hard brittle, white stocks in large fused opaque white-stone like masses having a dense crystalline fracture in small pellets/flakes.
- it is very delinquent and one of the strongest base , acts as a saponifying agent which is used in industrial purposes.
- It is an important industrial chemical as it is used on its own and is also used as a raw material in the production of other chemicals. The basis for the production of sodium hydroxide is the electrolysis of brine.
To know more about sodium hydroxide visit :
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Answer:
1.5 mol
Explanation:
Step 1: Given data
- Volume of argon gas: 33 L
- Standard temperature: 273.15 K
Step 2: Calculate the moles corresponding to 33 L of argon at standard temperature and pressure (STP)
At STP, 1 mole of argon gas occupies 22.4 L.
33 L × 1 mol/22.4 L = 1.5 mol
