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dedylja [7]
2 years ago
10

What is the name of the configuration management procedure that involves the collection of information about a system under norm

al operating conditions, to be used as a comparison when conditions are abnormal
Chemistry
1 answer:
raketka [301]2 years ago
5 0

The name of the configuration management procedure that involves the collection of information about a system under normal operating conditions is Baselining.

<h3>What is Baselining?</h3>

Baselining is a management process used to analyze a collection of information about a particular system.

This procedure (Baselining) is well known to analyze computer performance in a given network.

In conclusion, the name of the configuration management procedure that involves the collection of information about a system under normal operating conditions is Baselining.

Learn more about Baselining here:

brainly.com/question/25836560

#SPJ1

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33 protons 36 electrons 45 neutrons
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The temperature of a substance increases when the ____________________ energy of the substance increases.
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Read 2 more answers
The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

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