The strength of the friction doesn't matter. Neither does the distance or the time the asteroid takes to stop. All that matters is that the asteroid has
1/2 (mass) (speed squared)
of kinetic energy when it lands, and zero when it stops.
So
1/2 (mass) (original speed squared)
is the energy it loses to friction in order to come to rest.
Answer:
20 m
Explanation:
From the equation of motion,
S = ut+1/2gt²................................. Equation 1
Where S = Height, u = initial velocity, t = time, g = acceleration due to gravity.
Note: Because the rocked is being dropped from a height, acceleration due to gravity is positive (g), and initial velocity (u) is negative
Given: t = 2.0 s, g = 10 m/s², u = 0 m/s (dropped from height)
Substituting into equation 1
S = 0(2) + 1/2(10)(2)²
S = 5(4)
S = 20 m
Hence the height of the the cliff above the pool is 20 m
Answer:
size of popcorn seed may meet the scaled earth size of x = 0.07312 in.
Explanation:
Given:-
- The diameter of actual sun, Ds = 1.3927 * 10^6 km
- The diameter of model sun ball, ds = 8 in
- The diameter of the actual earth, De = 12,742 km
Find:-
How large would be the earth model
Solution:-
- We can use the actual diameters of the earth and sun to develop the ratio of earth diameter to that of sun. The direct ratio can be used to model the diameter of earth for the scale model
Sun Earth
Actual : 1392700 km 12,742 km
Scale : 8 in x
- Use direct relations and solve for x:
x = (8 in)*(12,742 km ) / ( 1392700 km )
x = 0.07312 in.
- From the given options apple, grapefruit and marble diameters are larger than 1 inch. So only the size of popcorn seed may meet the scaled earth size of x = 0.07312 in.
Answer:
what do you need help with? Like which type of print each image is?
Explanation:
