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alekssr [168]
3 years ago
7

A car speeds up from 3 m/s to 10 m/s in 8 s. How far does the car travel while doing this? 2. A

Physics
1 answer:
yarga [219]3 years ago
5 0

Initial velocity=u=3m/s

Final velocity=v=10m/s

Time=t=8s

\boxed{\sf Acceleration=\dfrac{v-u}{t}}

\\ \sf\longmapsto Acceleration=\dfrac{10-3}{8}

\\ \sf\longmapsto Acceleration=\dfrac{7}{8}

\\ \sf\longmapsto Acceleration=0.8m/s^2

  • Distance =s

Using second equation of motion

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto s=3(8)+\dfrac{1}{2}(0.8)(8)^2

\\ \sf\longmapsto s=24+0.4(64)

\\ \sf\longmapsto s=24+25.6

\\ \sf\longmapsto s=49.6m

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A car accelerates at a rate of 13m/s^2[S]. If the car's initial velocity is 120km/h[N]. What will its final velocity be in m/s,
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3 years ago
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then as per Gauss' law we have

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Now if we have a situation that the point lies outside the cylinder

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