Question

A car speeds up from 3 m/s to 10 m/s in 8 s. How far does the car travel while doing this? 2. A

Answer 1

Initial velocity=u=3m/s

Final velocity=v=10m/s

Time=t=8s

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto Acceleration=\dfrac{10-3}{8}$

$\\ \sf\longmapsto Acceleration=\dfrac{7}{8}$

$\\ \sf\longmapsto Acceleration=0.8m/s^2$

• Distance =s

Using second equation of motion

$\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2$

$\\ \sf\longmapsto s=3(8)+\dfrac{1}{2}(0.8)(8)^2$

$\\ \sf\longmapsto s=24+0.4(64)$

$\\ \sf\longmapsto s=24+25.6$

$\\ \sf\longmapsto s=49.6m$