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vekshin1
3 years ago
11

Explain how to measure volume using a graduated cylinder

Physics
1 answer:
Reil [10]3 years ago
6 0
Put object into cylinder and notice the volume increased. Difference of volume is the object's volume
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You hear a thunder 3 seconds after you see lightning. How far away is the storm?
kondor19780726 [428]
3 seconds (330 m) / second =
990 meter
3 0
3 years ago
Why is their displacement the same when the distance each traveled was different?
motikmotik
Displacement is how far something is from its starting position

for example if X moved 10 feet, turned around and moved 30 feet, its distance would be 40, but the displacement would be 20,
and if Y Moved 2 feet, and turned around and moved 22 feet, its distance would be 24, but its displacement would also be 20
4 0
4 years ago
Determine the magnitude as well as direction of the electric field at point A, shown in the above figure. Given the value of k =
DedPeter [7]

Answer:

The electric field is 9.3 x 10^12 N/C and the direction is away from the charge.

Explanation:

charge, Q = 12.5 C

distance, d = 11 cm = 0.11 m

Let the electric field is E.

E =\frac{K Q}{d^2}\\\\E = \frac{9\times 10^9\times 12.5}{0.11\times 0.11}\\\\E = 9.3\times 10^{12} N/C

The direction of electric filed is away from the charge.

3 0
3 years ago
What does a switch in an electrical circuit do?
PolarNik [594]

Answer:

It allows electrons to flow from one part of the circuit to another

when it is closed.

Explanation:

hope this helps <3 !!

5 0
3 years ago
The emf of the battery is 1.5 V. In Nichrome there are 9 × 1028 mobile electrons per m3, and the mobility of mobile electrons is
kolezko [41]

Answer:

The number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second

Explanation:

Given;

emf of the battery, V = 1.5 V

electron density, = 9 × 10²⁸ mobile electrons per m³

mobility of electron, u = 7 × 10⁻⁵ (m/s)/(N/C)

length of thin wire, L = 6 cm = 0.06 m

cross sectional area of the thin wire, A = 1.3 x 10⁻⁸ m²

The magnitude of the electric field in the thin wire is given by;

E = V/L

E = (1.5) / (0.06)

E = 25 N/C

the number of electrons entering the thin wire every second is given by;

e/s = mobility \ x \ Electric \ field\\\\number \ of \ electrons \ per \ second =\frac{7*10^{-5} (m/s)}{N/C} *25 (N/C)\\\\number \ of \ electrons \ per \ second = 1.75*10^{-3} \ m/s

Therefore, the number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second

5 0
3 years ago
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