If he keeps that pace he will be at the 34 yard line
Answer:
True
Explanation:
the horse pull on the wagon but friction and the wight + gravity make the wagon pull on the horse ( newton's 2ed law)
To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.
Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds
Horizontal distance
=0.335s*1.2m/s
=0.402 meters
Newton's first law of motion is an object in motion stays in motion until acted upon by another force. Driving at 30 mph in a car is going to stay constant until you crash the car into a wall, stopping the car.
To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.
I will also attach a free body diagram that allows a better understanding of the problem.
For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore
Here,
m = Net mass
= Angular velocity
r = Radius
W = Weight
N = Normal Force
The net mass is equivalent to
Then,
Replacing we have then,
Solving to find the angular velocity we have,
Therefore the angular velocity is 0.309rad/s
