If 3 grams of active ingredient are needed to make 1 pint of a suspension, how much active ingredient is needed to make 1 gallon

Question

3 years ago

15

of the suspension?

2 answers:

Illusion [34] · Answer 1 · 2022-04-14T01:55:09+03:00

7 0

Answer: 18 Grams

Explanation:

ki77a [65] · Answer 2 · 2022-04-14T00:40:38+03:00

Answer:

25mL of active ingredient is needed to make 1 gallon of the suspension

Explanation:

3 grams of active ingredient are needed to make 1 pint (16 ounces = 16×28.35 grams = 453.6 grams) of the suspension

Volume active ingredient needed to make 1 gallon (3.7854L = 3.7854×1000mL = 3785.4mL) = 3785.4mL × 3g/453.6g = 25mL