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34kurt
3 years ago
14

What volume of 7.68 M NaOH (aq) will neutralize 1.15 L of 2.35 M H2SO4 (aq) ?

Chemistry
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

hmm lemme think bur it will take a while

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The church believes all of these except?
pav-90 [236]
I believe it is still A with the current state of things, but there is talk in the church of reforming to allow women priests.
6 0
3 years ago
The solubility of k2cr2o7 in water is 125 g/l at 20 °c. a solution is prepared at 20 °c that contains 6.0 grams of k2cr2o7 in 50
Pachacha [2.7K]
The solubility is the guide to the maximum amount of solute that can be dissolved in a certain amount of solvent at a certain temperature to make a saturated solution. Any amount less than this would result to unsaturated, while any amount more would result to saturated.

6 g/(50 mL * 1 L/1000 mL) = 120 g/L

Since it is less than the solubility of 125 g/L, then <em>this solution is unsaturated</em>.
5 0
3 years ago
Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M
liberstina [14]

Answer:

= \mathbf{C_3H_6O}

Explanation:

From the given information, since the molecular mass of the ion M+ is not given;

Let's assume M+ = 58.0423

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we will need to divide the mass by 13, after dividing it;

The quotient n = no. of carbon; &

The addition of the quotient (n) with the remainder r =  no. of hydrogen.

So;

\dfrac{58}{13}= 4 \ remainder \ 6

So;

C_nH_{n+r} = C_4H_{4+6}

= C_4H_{10}

From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing CH_4. Also, since the mass is an even number then Nitrogen is 0.

So, we have:

= \mathbf{C_3H_6O}

6 0
3 years ago
Which element and how many atoms does each compound have in the picture?
Stells [14]
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The second one has 9 atoms and the elements sodium, carbon, and helium
7 0
3 years ago
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Dimas [21]

Answer:

Lewis structure in attachment.

Explanation:

Atoms of elements in and beyond the third period of the  periodic table form some compounds in which more than eight electrons surround the  central atom. In addition to the 3s and 3p orbitals, elements in the third period also  have 3d orbitals that can be used in bonding. These orbitals enable an atom to form  an <u>expanded octet</u>.

The central Xe atom in the XeF₄ molecule has <u>two</u> unbonded electron pairs and <u>four</u> bonded electron pairs in its valence shell.

8 0
3 years ago
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