Question

1) Given the balance equation below. Calculate how much Na3PO4 in grams you

Answer 1

Answer:

136.67 g of Na3PO4 is required to create 100 gram of NaOH.

Explanation:

The balanced equation:

$Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}$

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

or

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

$\frac{164}{120}$

100 grams of NaOH is produced from =

$\frac{164}{120}\times100$ gram of Na3PO4

calculate,

= 136.67 g